The surface area of the figure given is of: 61.3 yd².
<h3>What is the combined surface area of a figure?</h3>
The combined surface area of a figure is the area of each figure.
This figure is composed by:
- A triangle with base 6 yd and one leg 11.4 yd.
The area of the circle is given as follows:

For the triangle, we need to find it's height, which is the <u>leg of a right triangle, in which one of the sides is 3 and the hypotenuse is 11.4</u>, hence:
h² + 3² = 11.4²

h = 11 yd.
Hence the area of the triangle is:
A = 0.5 x 6 x 11 = 33 yd²
The surface area of the figure is:
9pi + 33 yd² = 61.3 yd².
More can be learned about the surface area of at brainly.com/question/21208177
#SPJ1