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Nonamiya [84]
2 years ago
13

Instructions: Find the surface area of the figure below. Round your answers to the nearest tenth, if necessary.

Mathematics
1 answer:
Y_Kistochka [10]2 years ago
6 0

The surface area of the figure given is of: 61.3 yd².

<h3>What is the combined surface area of a figure?</h3>

The combined surface area of a figure is the area of each figure.

This figure is composed by:

  • A circle of radius 3 yd.
  • A triangle with base 6 yd and one leg 11.4 yd.

The area of the circle is given as follows:

A = \pi r^2 = \pi \times 3^2 = 9\pi

For the triangle, we need to find it's height, which is the <u>leg of a right triangle, in which one of the sides is 3 and the hypotenuse is 11.4</u>, hence:

h² + 3² = 11.4²

h = \sqrt{11.4^2 - 3^2}

h = 11 yd.

Hence the area of the triangle is:

A = 0.5 x 6 x 11 = 33 yd²

The surface area of the figure is:

9pi + 33 yd² = 61.3 yd².

More can be learned about the surface area of at brainly.com/question/21208177

#SPJ1

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Answer:

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Step-by-step explanation:

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so equation is

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given focus is (-5, -3) so h= -5  and k+p = -3

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k + 1.5 = -3

subtract 1.5 on both sides

k = -4.5

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focus at (10, -4), and directrix y = 6.

Directrix y=6 so its  a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

distance between focus and directrix = 2p

distance between -4  and y=6 is -4-6=-10

2p = -10

p = -5

Focus is (h, k+p)

given focus is (10, -4) so h= 10  and k+p = -4

k+p=-4, plug in 5 for p

k - 5 = -4

add 5 on both sides

k = 1

(x-h)^2 = 4p(y-k)

(x-10)^2= 4(-5) (y-1)

(x-10)^2= -20(y-1)

divide by -20 on both sides and add 1 on both sides

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<span>1/2</span>

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