Answer:
a_n = 28-2n
Step-by-step explanation:
Given sequence is:
26,24,22,20
We can see that the difference between consecutive terms is same so the sequence is an arithmetic sequence
The standard formula for arithmetic sequence is:
Here,
a_n is the nth term
a_1 is the first term
and d is the common difference
So,
d = 24-26
= -2
a_1 = 26
Putting the values of d and a_1
Hence, the recursive formula for given sequence is: a_n = 28-2n ..
Q1. The answer is 4(2x - 3)(2x + 1)
16x² – 16x – 12 = 4 * 4x² - 4 * 4x - 4 * 3 =
= 4(4x² - 4x - 3) =
= 4(4x² + 2x - 6x - 3) =
= 4(2x * 2x + 2x - (2x * 3 + 3)) =
= 4(2x(2x + 1) - (3(2x + 1))) =
= 4((2x + 1)(2x - 3)) =
= 4(2x - 3)(2x + 1)
Q2. The answer is 3(x + 8)(x - 1)
3x² + 21x – 24 = 3 * x² + 3 * 7x - 3 * 8 =
= 3(x² + 7x - 8) =
= 3(x *x - x + 8x - 8) =
= 3((x(x - 1) + 8(x - 1)) =
= 3(x + 8)(x - 1)
Answer: p = 30 q = 30 (if not touching edge of hexagon but if it is touching edge one of the pairs) then p or q = 120 and p and q = 30
Step 1) Sum of an interior angle of a polygon = 720 degree where n = 6 as 6 exterior sides = (n-2) * 180 = (6-2) * 180 = 4 * 180 = 720 degree Where the measure of each angle of a hexagon = 720/ 6 = 120 degree Step 2) Then show 3 angle letter names = 180 degree Step 3) Angle name letters + 2 angle (other two names letters inside within triangle) add up to 180 degree Step 3) State since triangle name (of all letters within one triangle) is Isosceles Step 4) <u>Triangle (state same triangle letters with number 2 in front) = 180 - 120 = 60 then state triangle (letter name) / 2 = 30 degrees </u>obviously the 120 and 60 differentiates if not a hexagon to a pentagon if not a hexagon = (3 *180) / 5 = 108 then due to isosceles (180 - 108)/ 2 = 72/2 = 36 degree for a p<u>entagon </u>or 30 degree each for p + q for a <u>hexagon</u> etc
Answer:
12
Step-by-step explanation:
-4 * -3
12
When you multiply two negatives, you get a positive number.
Hope this helps ^-^
<h3><em><u>given</u></em><em><u>:</u></em></h3>
<em><u>length</u></em><em><u>=</u></em><em><u> </u></em><em><u>15cm</u></em>
<em><u>width</u></em><em><u>=</u></em><em><u> </u></em><em><u>7cm</u></em>
<h3><em><u>to</u></em><em><u> </u></em><em><u>find</u></em><em><u>:</u></em></h3>
<em><u>area</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>rectangle</u></em><em><u>.</u></em>
<h3><em><u>solution</u></em><em><u>:</u></em></h3>
<em><u>area</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>rectangle</u></em><em><u>=</u></em><em><u> </u></em><em><u>length</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>width</u></em><em><u> </u></em>
<em><u>a</u></em><em><u>=</u></em><em><u> </u></em><em><u>l</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>w</u></em>
<em><u>a</u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>5</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>7</u></em>
<em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>0</u></em><em><u>5</u></em><em><u> </u></em><em><u>cm</u></em><em><u>^</u></em><em><u>2</u></em>