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likoan [24]
3 years ago
10

Please hurry Arrange the steps of the engineering design process in the correct sequence.

Computers and Technology
1 answer:
AnnZ [28]3 years ago
6 0

Answer:The Nine steps  of the engineering design process

  1. <u>Identify the Problem</u>-Defining the problem
  2. Finding solutions through Brainstorming technique
  3. Conducting a background research/Survey
  4. Developing the solution-Creating an array of solutions
  5. Selecting the best solution
  6. Building a prototype
  7. Testing and redesigning
  8. Improve the design-Specifying the requirement
  9. Communicating the result

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What is the wave speed of a wave that has a frequency of 100 Hz and a wavelength of 0.30m?
swat32

<u><em>Answer:</em></u>

<u><em>The speed is  </em></u>

<u><em>= </em></u>

<u><em>30 </em></u>

<u><em>m </em></u>

<u><em>s </em></u>

<u><em>− </em></u>

<u><em>1 </em></u>

<u><em> </em></u>

<u><em>Explanation: </em></u>

<u><em>The speed of a wave is given by </em></u>

<u><em> </em></u>

<u><em>speed </em></u>

<u><em>( </em></u>

<u><em>m </em></u>

<u><em>s </em></u>

<u><em>− </em></u>

<u><em>1 </em></u>

<u><em>) </em></u>

<u><em>= </em></u>

<u><em>frequency(Hz) </em></u>

<u><em>× </em></u>

<u><em>wavelength (m) </em></u>

<u><em> </em></u>

<u><em>The frequency is  </em></u>

<u><em>f </em></u>

<u><em>= </em></u>

<u><em>100 </em></u>

<u><em>H </em></u>

<u><em>z </em></u>

<u><em> </em></u>

<u><em>The wavelength is  </em></u>

<u><em>λ </em></u>

<u><em>= </em></u>

<u><em>0.3 </em></u>

<u><em>m </em></u>

<u><em> </em></u>

<u><em>The speed is </em></u>

<u><em> </em></u>

<u><em>v </em></u>

<u><em>= </em></u>

<u><em>λ </em></u>

<u><em>f </em></u>

<u><em>= </em></u>

<u><em>0.3 </em></u>

<u><em>⋅ </em></u>

<u><em>100 </em></u>

<u><em>= </em></u>

<u><em>30 </em></u>

<u><em>m </em></u>

<u><em>s </em></u>

<u><em>− </em></u>

<u><em>1 </em></u>

<u><em> </em></u>

<u><em></em></u>

<u><em></em></u>

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6 0
3 years ago
Consider a set of mobile computing clients in a certain town who each
poizon [28]

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - -  cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i  clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we  find the max flow in N

⇒ connecting cl-i clients to  bs-j stations

      like (cl-i, bs-j) = 1

   if f(cl-i, bs-j)  = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected                f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected  to bs-j(stations)   f(cl-i,bs-j) = 1 (o otherwise)

   f(bs-j,t) = no of clients  (cl-i)  connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff    f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

5 0
3 years ago
What are Three types of informational references
Irina-Kira [14]

Answer:

There are many types of information al references such as Encyclopedias, dictionaries, thesaurus Almanacs, atlases, thesauruses, Atlases, almanacs, and encyclopedias.

Explanation:

There are also informational websites. The way to find this is to look at the website url to see if it ends in .gov, .edu, and .org . But make sure you cite your source so you don't plagiarize.

If you don't have any questions feel free to ask in the comments.

3 0
3 years ago
Read 2 more answers
Carlos has noticed that he has a duplicate slide in his presentation. He would like to delete it. He should _____.
vagabundo [1.1K]

Answer:

click on the slide in normal view and press delete

Explanation:

i don't know if this is right but you can click edit and delete it like that.

8 0
3 years ago
QUESTION 6 Which of the following is a class A IPv4 address? a. 118.20.210.254 b. 183.16.17.30 c. 215.16.17.30 d. 255.255.0.0
shepuryov [24]

Answer:

a. 118.20.210.254

Explanation:

Here are the few characteristics of Class A:

First bit of the first octet of class A is 0.

This class has 8 bits for network and 24 bits for hosts.

The default sub-net mask for class A IP address is 255.0.0.0

Lets see if the first bit of first octet of 118.20.210.254 address is 0.

118 in binary (8 bits) can be represented as : 1110110

To complete 8 bits add a 0 to the left.

01110110

First bit of the first octet of class A is 0 So this is class A address.

For option b the first octet is : 183 in the form of bits = 10110111 So it is not class A address

For option c the first octet is 215 in the form of bits = 11010111 So it is not class A address

For option d the first octet is 255 in the form of bits = 11111111. The first bit of first octet is not 0 so it is also not class A address.

3 0
3 years ago
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