Question

Robert uses a wheelbarrow to haul wood from the back yard to his neighbor's house located 9 meters away. If he takes two breaks evenly when pushing the wheelbarrow to its destination, at which distance will he reach his first break?
Robert has 36 pieces to take, but can only take 9 each time. What distance in meters will he travel to move all the wood?

Answer 1

Answer:

3 meters

63 meters

Step-by-step explanation:

In order for his two breaks to occur after even distances, simply divide his total path in three:

$B = \frac{9}{3}\\ B=3\ meters$

He will reach his first break after 3 meters.

If he can only take 9 pieces at a time the number of trips required is:

$n=\frac{36}{9}\\ n=4$

Note that he will have to back to the back yard for the first three trips (traveling back the 9 meters path). The total distance traveled is:

$d= 3*(9+9)+9\\d=63\ meters$

He will travel 63 meters.