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2 years ago

MAJORR HELP!!!! In the graph, what are the x- and y-coordinates of the center?

Mathematics

1 answer:

Helen [10]2 years ago

3 0

Answer:

D: (-1,2)

Step-by-step explanation:

The X coordinate is between 2 and -4. There is a difference of 6, so you should do -4 + (6/2) = -1.

so the X coordinate is -1

The y coordinate is between 0 and 4. There is a difference of 4, so you should do 0 + (4/2) = 2.

so the y coordinate is 2

This results in the centre being (-1,2)

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Ally ran 5 miles in 36 minutes. If Ally runs at the same rate, how long would it take her to run 1 mile?

Ne4ueva [31]

Answer:

7.2 Minutes

Step-by-step explanation:

Use Ratios

Miles : Minutes

5:36

Divide Both Sides By 5

1:7.2

It will Take Ally 7.2 Minutes To Run 1 Mile

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2 years ago

Read 2 more answers

******PLEASE HELP!!******

expeople1 [14]

Answer:

$9^{4}$

Step-by-step explanation:

9^-5 = 9^4 x 9^-9

4-9 = -5

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2 years ago

Christine has $875.83 In her savings account the account pays 9% compounded monthly. Christine does not make any deposits or wit

Karolina [17]

Answer: the account earns interest of $40.16

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 875.83

r = 9% = 9/100 = 0.09

n = 12 because it was compounded 12 times in a year.

t = 6 months = 6/12 = 0.5 year

Therefore,.

A = 875.83(1+0.09/12)^0.5 × 12

A = 875.83(1+0.0075)^6

A = 875.83(1.0075)^6

A = 915.99

The interest that she earns is

915.99 - 875.83 = $40.16

7 0

2 years ago

A well respected wild life researcher recently conducted a

Marina CMI [18]

Answer:

Claim : men weigh of wild jackalopes is 69.9

The null hypothesis : H0 : μ = 69.9

Alternative hypothesis : H1 : μ ≠ 69.9

Test statistic = −2.447085

P value = 0.0174

Conclusion :

Fail to Reject the Null hypothesis

Step-by-step explanation:

From the question given :

The claim is that : mean weight of wild jackalopes is still the same as 10 years with a mean weight of 69.9 lbs.

The null hypothesis : H0 : μ = 69.9

Alternative hypothesis : H1 : μ ≠ 69.9

Using calculator :

Sample mean (x) = 66

Sample standard deviation (s) = 12.345

The test statistic t :

(x - μ) / (s/√n)

n = sample size = 60

(66 - 69.9) / (12.345 / √60)

t = −2.447085

P value at α 0.01, df = 59 is 0.0174

Since the p value is > 0.01, the result is not significant at 0.01. Therefore, we fail to reject the Null

7 0

2 years ago

Find the solution of the given initial value problem. ty' + 2y = sin t, y π 2 = 9, t > 0 y(t) =

Helen [10]

For the ODE

$ty'+2y=\sin t$

multiply both sides by t so that the left side can be condensed into the derivative of a product:

$t^2y'+2ty=t\sin t$

$\implies(t^2y)'=t\sin t$

Integrate both sides with respect to t :

$t^2y=\displaystyle\int t\sin t\,\mathrm dt=\sin t-t\cos t+C$

Divide both sides by $t^2$ to solve for y :

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac C{t^2}$

Now use the initial condition to solve for C :

$y\left(\dfrac\pi2\right)=9\implies9=\dfrac{\sin\frac\pi2}{\frac{\pi^2}4}-\dfrac{\cos\frac\pi2}{\frac\pi2}+\dfrac C{\frac{\pi^2}4}$

$\implies9=\dfrac4{\pi^2}(1+C)$

$\implies C=\dfrac{9\pi^2}4-1$

So the particular solution to the IVP is

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac{\frac{9\pi^2}4-1}{t^2}$

$y(t)=\dfrac{4\sin t-4t\cos t+9\pi^2-4}{4t^2}$

6 0

2 years ago