We have an isosceles triangle;
A=opposite angle side a.
B=opposite angle side b.
C=opposite angle side c.
A=B
Method 1:
We can divide the isosceles triangle in two right triangles,
hypotenuse=7
side=9/2=4.5
B=A=arccossine (4.5/7)=49.994799...º≈50º
C/2=90º-50º=40º ⇒ C=2*40º=80º
Answer:
a=7; A=50º
b=7; B=50º
<span>c=9; C=80º
Method 2:
Law of cosines:
a²=b²+c²-2bcCosA ⇒CosA=(a²-b²-c²)/(-2bc)
CosA=(49-49-81) / (-126)=0.642857
A=arco cos (81/126)≈50º
B=A=50º
A+B+C=180º
50º+50º+C=180º
C=180º-100º
C=80º
Answer:
</span>a=7; A=50º
b=7; B=50º
<span>c=9; C=80º</span>
Answer: False
Step-by-step explanation:
You didn't give the coordinate plane that I was supposed to use while helping you.
Answer:
26in^2
Step-by-step explanation:
5 time 4 is 20in^2. plus 2 times 3 is 6in^2.
add 20 and 6 then you get 26in^2.
According to the diagram the answer is 36degree
The answer is the option 3. (the arrow aimed to the center of the polygon)
Why?. Because the particle changed the direction of its movement due to a force inclined respect the motion and aimed to the center. Take in account that the vectors net force and acceleration are parallel.
