<h3>
Answer: Shift the graph of g(x) up 5 units</h3>
Reasoning:
We see that f(x) = g(x)+5. Whatever the output of g(x) is, we add on 5 to get the output of f(x). The input is x, while the output is y. Adding 5 to the y output is what shifts every point on g(x) up 5 units to move the entire curve up 5 units.
Answer:
Step-by-step explanation:
We can multiply -4x by both terms inside the parentheses.
Hope this helped!
If you multiply 600 by 0.05 by 2 you will get $60.00 as your balance of your account.
Answer:
a)<em> k(x) = 5x - 2</em>
x = 5(y) - 2
5y = x + 2
y = (x+2)/5
<u>k-¹(x) = (x+2)/5</u>
b) <em>h</em><em>(</em><em>x</em><em>)</em><em> </em><em>=</em><em> </em><em>(</em><em>x</em><em>+</em><em>1</em><em>0</em><em>)</em><em>/</em><em>(</em><em>x</em><em>-</em><em>3</em><em>)</em><em> </em>
x = (y+10)/(y-3)
x(y-3) = y + 10
xy -3x = y + 10
xy - y = 3x + 10
y(x-1) = 3x + 10
y = (3x + 10)/(x-1)
<u>h-¹(x) = (3x+10)/(x-1)</u>
Not sure how to give a hint without blatantly giving the answer but...
Consider an n - digit number in base b.
That is N=an−1an−2.....a0=∑k=0akbk
N
=
a
n
−
1
a
n
−
2
.
.
.
.
.
a
0
=
∑
k
=
0
a
k
b
k
Note aka
k
<
b
so we can easily show NN
<
b
n
(may have to repeat and argue inductively.
And presumably to be n - digit than an−1≠0
a
n
−
1
≠
0
so N≥bn−1
N
≥
b
n
−
1
.
So we have: every n digit number is between bn−1
b
n
−
1
inclusively and bn
b
n
exclusively. This should be blindingly obvious to us if b=10
b
=
10
.
So... that's a really important and fundamental result. Remember and use it.
