Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of
C because you factor it out
Answer:
B
Step-by-step explanation:
B is in Quadrant III.
B is the answer.
The answer is 6
hope this helped
Answer:
x=-2
Step-by-step explanation:
5x+4=-6 so basically what you want to do is try to get x by itself
step 1 subtract 4 from each side
5x=-10
step 2 divide each side by 5
x=-2
