Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:
x = 17
Step-by-step explanation:
The sum of all angle measures in any triangle is 180 degrees.
- Thus, 23 + 5x - 18 + 90 = 180.
Step 1: Simplify both sides of the equation.
Step 2: Subtract 95 from both sides.
Step 3: Divide both sides by 5.
Step 4: Check if solution is correct.
Thus, x = 17.
Answer:
315,360 I had to assume you needed that number, 292000+8%=315360
Answer:
4584607 is your correct answer
The center of the clock is taken as the origin.The clock is a circle with a diameter 10 units.Radius is half the diameter .Radius = 10 ÷2= 5 units.
The clock is divided in four quadrants .On x axis y=0 and on y axis x=0.
When it is 12 o'clock the hour hand is on positive of y axis.Coordinates of the point at 12 o'clock=(0,5)
When it is 3 o 'clock the hour hand is on positive of x axis .Coordinate of the point at 3o'clock is (5,0)
When it is 6 o'clock the hour hand is on negative of y axis .The coordinates of the point at 6o'clock is (0,-5)
At 9o'clock the hour hand is on negative of x axis .The coordinate of the point at 6o'clock is(-5,0)
