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Romashka [77]
3 years ago
10

Round 1.07 to the tenths place.

Mathematics
1 answer:
galben [10]3 years ago
5 0
Answer: 1.10
Work: 5 or more raise the next digit, 4 or less keep it
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14)
klio [65]

Answer:

y = -1/4x -2

Step-by-step explanation:

the perpendicular slope would be -1/4

2 = -1/4 (-16) + b

b = -2

the equation should be y = -1/4x -2

None of the answers you typed could be correct.

5 0
4 years ago
0= -16t^2 + 98 solve for t​ round to the nearest tenth if needed
Lunna [17]

Answer:

t = 7 • ± √2 = ± 9.8995

Step-by-step explanation:

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%20%3D%20ln%205" id="TexFormula1" title="e^{2x} = ln 5" alt="e^{2x} = ln 5" align=
KiRa [710]
e ^{2x} = ln5

Solve for the real domain

e ^{2x} = ln(5)

if f(x) =g(x), then ln(f(x))= ln(g(x))

ln(e ^{2x} ) = ln(ln(5))

Solve : <span>ln(e ^{2x} ) = ln(ln(5))
</span>
use the logarithmic definition :

ln(e^{f(x)} ) = f(x)

ln(e^{2x} ) = 2x

2x=ln(ln(5))

Divide both sides by 2 :

\frac{2x}{2} = \frac{ln(ln(5))}{2}

x= \frac{ln(ln(5))}{2}

hope this helps!

8 0
3 years ago
Help for brainlest what can be use ti
Sophie [7]

Answer:

2x(5+13)

Step-by-step explanation:

add then multiply by 2

3 0
3 years ago
Read 2 more answers
Find the smallest possible integer value of k for which 264k is a perfect square.
wolverine [178]

Step-by-step explanation:

264k

= 2³ * 3 * 11 * k

Hence, k = 2 * 3 * 11 = 66.

3 0
3 years ago
Read 2 more answers
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