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strojnjashka [21]
3 years ago
12

Solve the system using elimination 5x-y=0 3x+y=24

Mathematics
1 answer:
LenKa [72]3 years ago
8 0
5x-y=0
3x+y=24
2x=-24
x=-12
-36+y=-24
y=-24+36
y=12
HOPE I HELPED!!!
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For which positive integer values of $k$ does $kx^2+20x+k=0$ have rational solutions? Express your answers separated by commas a
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Answer:

-10,10

Step-by-step explanation:

The given quadratic equation is

k {x}^{2}  + 20x + k = 0

The discriminant of this equation is given by;

D =  {b}^{2}  - 4ac

where a=k, b=20, c=k

For rational solutions, the discriminant must be zero.

{20}^{2}  - 4 \times k \times k = 0

Simplify to get:

400 - 4  {k}^{2}  = 0

This implies that:

400  = 4  {k}^{2}

100 =  {k}^{2}

Take square root to get:

k =   \pm\sqrt{100}

k =  \pm10

k =  - 10 \: or \: k = 10

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Arte-miy333 [17]

Answer:

goh(x)=x^3+12x^2+49x+68

Step-by-step explanation:

g(x) = x^3+x

h(x)=x+4

We have to find

goh(x)

goh(x) = g(h(x))=g(x+4)

If g(x) = x^3+x

g(x+4) = (x+4)^3+(x+4)

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Hence our answer is

goh(x)=x^3+12x^2+49x+68

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Answer:

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Step-by-step explanation:

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2 years ago
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Answer:

no

Step-by-step explanation:

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