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fiasKO [112]
3 years ago
13

Write the point-slope form of the line that passes through (5,5) and is perpendicular to a line with a slope of 1/4 include all

of your work in your final answer.
Mathematics
1 answer:
amid [387]3 years ago
3 0

<u>Answer:</u>

The point-slope form of the line that passes through (5,5) and is perpendicular to a line with a slope of \frac{1}{4} is 4x + y -25 = 0

<u>Solution:</u>

The point slope form of the line that passes through the points \left(x_{1} y_{1}\right) and perpendicular to the line with a slope of “m” is given as  

\bold{y-y_{1}=-\frac{1}{m}\left(x-x_{1}\right)} ---- eqn 1

Where “m” is the slope of the line. x_{1} \text { and } y_{1} are the points that passes through the line.

From question, given that slope “m” = \frac{1}{4}

Given that the line passes through the points (5,5).Hence we get

x_{1}=5 ; y_{1}=5

By substituting the values in eqn 1 , we get the point slope form of the line which is perpendicular to the line having slope \frac{1}{4}can be found out.

y - 5 = -4(x - 5)

y - 5 = -4x + 20

on simplifying the above equation, we get

y - 5 + 4x -20 = 0

4x + y - 25 = 0

hence the point slope form of given line is 4x + y - 25 = 0

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I hope this helps you

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3 years ago
A letter is randomly chosen from the word EXCELLENT. Write each probability as a fraction, decimal, and a percent.
Sergio [31]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete. A complete question is in the form:

A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.

Solution:

The total number of letters found in the word EXCELLENT = 9

i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3

Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3

probability that letter chosen is a vowel = 1/3 = 0.333 = 33.3%

ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6

Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3

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3 years ago
X+5/2 + x−3/3 =3 1/6
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Step-by-step explanation:

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