Answer:
Probability of choosing a chocolate candy = 0.538
Step-by-step explanation:
We are given that a bowl of candy contains 7 chocolate candies and 6 lemon candies.
Probability of choosing a chocolate candy = No. of chocolate candies ÷
Total no. of candies
= 7 ÷ 13 = 0.538
Therefore, the probability of choosing a chocolate candy is 0.538 .
53.846%
2/3 ≈ 0.6667
apply soh cah toa
sine=opposite/hypo
sine=4/6
sine=2/3
Batman
$6.60
6.20 x 3 = 18.60
6.90 x 4 = 27.60
18.60 + 27.60 = 46.20
46.20 ÷ 7 = 6.60
t=63
2t = 126
