The book value at the end of year 2 of the equipment depreciated using the sum-of-the-years’-digits method is $65,560.
<h3>What is the book value at the end of year 2? </h3>
Depreciation is a method used to expense the cost of an asset. Book value is the cost of the asset less the accumulated depreciation.
Sum-of-the-year digits = (remaining useful life / sum of the years ) x (Cost of asset - Salvage value)
Depreciation expense in year 1:
Sum of the years = 1 +2 +3 +4 + 5 + 6 + 7 + 8 + 9 + 10+ 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 210
Undepreciated life of the asset = 20
(20 / 210) x ($79,600 - 4,000) = 7200
Depreciation expense in year 2:
19 / 210 x ($79,600 - 4,000) = 6840
Book value = 79600 - 7200 - 6840 = $65,560
To learn more about depreciation, please check: brainly.com/question/25552427
For
the first question; we have a problem dealing with translations.
Our goal is to translate
the word problem into an algebraic one. So our numbers are
60, 2, and 5. Our variable, or the letter holding the unknown
number's place
value, is
N. <span>
</span>The
problem states that 60 is MORE THAN the PRODUCT of 5 and N. Focus
on the words I bolded and capitalized. These are your key words that
tells you what operations
you need to use. Note that 'product' signals the operation of
multiplication (Since the answer you get from multiplying numbers is
called the 'product'.) and
'more than' signals the operation of addition (Because you are left
off with more than you originally had before adding). <span>
</span>Now
that we know that our algebraic expression contains multiplication,
addition, letter N and the numbers 2 and 5; we can start plugging the
numbers in.<span>
</span>60
= 2 (more than) + (product of) 5N. The answer for the first
attachment is
B. <span>
</span>_____________________________________________________________<span>
</span>All
we need to do for the AB problem (Question 25 on your material) is
solve AB.<span>
</span>Note
1: When a problem has no operation separating two letters or numbers,
this means multiplication.<span>
</span>Note
2: A and B are variables. Variables are letters that stand for and
hold the place of our unknown quantities. However, the values are not
unknown anymore given the fact that the question tells us that A= 42
and B = 2. Thus we substitute A with 42 and B with 2, then work from
there. 42 * 2 =84. Answer = A.
____________________________________________________________________
And
finally, for question 26, we use PEMDAS. P = parenthesis (), E =
exponent x^2, M/D = x or /, A/S means + or subtraction.
According
to PEMDAS, we first solve what's parenthesis, which is 77 – 32.
Using mental math, 77 – 32 = 45. ( 7 – 3 = 4 and 7 – 2 = 5.). 5/9
* 45 is what we have left. 5 divided by 9 =0.5555555555555556.
0.5555555555555556 * 45 = 25. Answer is D.
The volume is twice that of the cube of width, so the width of the original prism is
.. ∛(16 cm³/2) = 2 cm
Length = 4 cm
Width = 2 cm
Height = 2 cm
For the first one, we add 2.7 to both sides to get x≥13. Next, we divide both sides by -0.84 to get x≥ 168/-0.84. SInce we multiplied or divided by a negative number, we switch the sign around and end up with x≥200
Your answer is C . good luck.
