Answer:
AB = 75
BC = 60
AC = 45
m∠A = 53°
m∠B = 37°
m∠C = 90°
Step-by-step explanation:
<u>Trigonometric ratios</u>

where:
is the angle- O is the side opposite the angle
- A is the side adjacent the angle
- H is the hypotenuse (the side opposite the right angle)
Given:

Therefore:
- side opposite angle A = BC = 60
- side adjacent angle A = AC = 45
To find the length of AB (the hypotenuse), use Pythagoras’ Theorem:

(where a and b are the legs, and c is the hypotenuse, of a right triangle)
⇒ AC² + BC² = AB²
⇒ 45² + 60² = AB²
⇒ AB² = 5625
⇒ AB = √5625
⇒ AB = 75
To find m∠A:



m∠C = 90° (as it is a right angle)
The interior angles of a triangle sum to 180°
⇒ m∠A + m∠B + m∠C = 180°
⇒ 53° + m∠B + 90° = 180°
⇒ m∠B = 180° - 53° - 90°
⇒ m∠B = 37°
Answer:
2x³+5x²+7x+5
Step-by-step explanation:
(x² + 4x² + x³ + x) + (x³ + x + 5x + 5)
(5x²+x³+x)+(x³+6x+5)
2x³+5x²+7x+5
Answer:
What kind of angles?
Step-by-step explanation:
What is your question?
What are the multoquestions? I can't help if they are not there.
Solution:
Given,
Volume of the-
First cube box=1728 in³
Second cube box=13824in³
We know that volume of cube =a³
So for the first box
a³= 1728 in³
a= 12 in
Now, surface area of the first box
6a²= 6×(12)²
= 864 in²
and for the second box
b³= 13824 in³
b= 24 in
Now, the surface area of the second box
6b²= 6×(24)²
= 3456 in²
Now, the ratio of the surface area of first box to the second box will be
864:3456
=1:4
The surface area of the larger of two boxes is
3456 in²