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lora16 [44]
3 years ago
8

Which expression could be used to determine the area of the square? A square has side lengths of 10.75 meters. (2)(10.75) (4)(10

.75) (10.75) squared (10.75) Superscript 4
Mathematics
1 answer:
kolezko [41]3 years ago
3 0

Answer:

Step-by-step explanation:

area of square=10.75² m²

or A=(10.75)(10.75)  m²

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PLEASE WILL GIVE 50 POINTS PLEASE ANSWER ​
leva [86]

Answer:

AB = 75

BC = 60

AC = 45

m∠A = 53°

m∠B = 37°

m∠C = 90°

Step-by-step explanation:

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

\sf \tan(A)=\dfrac{60}{45}

Therefore:

  • side opposite angle A = BC = 60
  • side adjacent angle A = AC = 45

To find the length of AB (the hypotenuse), use Pythagoras’ Theorem:

a^2+b^2=c^2

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

⇒ AC² + BC² = AB²

⇒ 45² + 60² = AB²

⇒ AB² = 5625

⇒ AB = √5625

⇒ AB = 75

To find m∠A:

\implies\sf \tan(A)=\dfrac{60}{45}

\implies\sf A=\tan^{-1}\left(\dfrac{60}{45}\right)

\implies\sf A=53^{\circ}\:(nearest\:degree)

m∠C = 90° (as it is a right angle)

The interior angles of a triangle sum to 180°

⇒ m∠A + m∠B + m∠C = 180°

⇒ 53° + m∠B + 90° = 180°

⇒ m∠B = 180° - 53° - 90°

⇒ m∠B = 37°

4 0
2 years ago
(x2 + 4x2 + x3 + x) + (x3 + x + 5x + 5)
yuradex [85]

Answer:

2x³+5x²+7x+5

Step-by-step explanation:

(x² + 4x² + x³ + x) + (x³ + x + 5x + 5)

(5x²+x³+x)+(x³+6x+5)

2x³+5x²+7x+5

3 0
3 years ago
How do I do angles of triangles​
BigorU [14]

Answer:

What kind of angles?

Step-by-step explanation:

What is your question?

7 0
3 years ago
Please help 30 points Really hard mulitiquestions
Alika [10]
What are the multoquestions? I can't help if they are not there.
5 0
3 years ago
Brian needs to start planning for an upcoming move. He is choosing two different size boxes to pack the majority of his stuff. T
GenaCL600 [577]

Solution:

Given,

Volume of the-

First cube box=1728 in³

Second cube box=13824in³

We know that volume of cube =a³

So for the first box

a³= 1728 in³

a= 12 in

Now, surface area of the first box

6a²= 6×(12)²

= 864 in²

and for the second box

b³= 13824 in³

b= 24 in

Now, the surface area of the second box

6b²= 6×(24)²

= 3456 in²

Now, the ratio of the surface area of first box to the second box will be

864:3456

=1:4

The surface area of the larger of two boxes is

3456 in²

5 0
3 years ago
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