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Maksim231197 [3]
4 years ago
12

SOLVING QUADRATIC EQUATIONS BY SQUARE ROOT 4m^2-1=-23

Mathematics
2 answers:
liraira [26]4 years ago
7 0
4m^2 -1 = -23 Add 1 to both sides 4m^2 = -22 then divide both sides by 4. m^2 = -11/2. Square root both sides. m = ((square root of 22)/2) times i
PtichkaEL [24]4 years ago
6 0
<span>4m^2-1=-23
</span>⇒ 4m^2= -23+1
⇒ 4m^2= -22
⇒ m^2= -22/4
⇒ m^2= -11/2
⇒ m is undefined for all m∈R (for m^2 is always ≥0 for all m∈R)
<span>
Final answer: </span>m is undefined for all m∈R~
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Answer:

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Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

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The formula used is: a_n= a_1r^{n-1}

We are given: third term = 6 i,e

a_3=a_1r(3-1)\\6=a_1r^2----eq(1)

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Dividing eq(2) and eq(3)

\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}

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Finding First term using eq(1)

a_3=a_1r^2\\6=a_1(2)^2\\6=a_1(4)\\a_1= \frac{6}{4}\\a_1= \frac{3}{2}

So, First term a₁ = 3/2 and common ratio r = 2

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