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4 years ago

SOLVING QUADRATIC EQUATIONS BY SQUARE ROOT 4m^2-1=-23

2 answers:

7 0

4m^2 -1 = -23 Add 1 to both sides 4m^2 = -22 then divide both sides by 4. m^2 = -11/2. Square root both sides. m = ((square root of 22)/2) times i

PtichkaEL [24]4 years ago

6 0

<span>4m^2-1=-23
</span>⇒ 4m^2= -23+1
⇒ 4m^2= -22
⇒ m^2= -22/4
⇒ m^2= -11/2
⇒ m is undefined for all m∈R (for m^2 is always ≥0 for all m∈R)
<span>
Final answer: </span>m is undefined for all m∈R~

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The manufacturer of an airport baggage scanning machine claims it can handle an average of 530 bags per hour. (a-1) At α = .05 i

fenix001 [56]

Answer:

Null hypothesis: $\mu \geq 250$

Alternative hypothesis: $\mu < 250$

$p_v =P(t_{15}$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not significantly lower than 530 at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=510$ represent the mean for the sample

$s=50$ represent the standard deviation for the sample

$n=16$ sample size

$\mu_o =530$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the claim thet the handle on average is 530 bags per hour:

Null hypothesis: $\mu \geq 530$

Alternative hypothesis: $\mu < 530$

We don't know the population deviation and the sample size is lees than 30, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{510-530}{\frac{50}{\sqrt{16}}}=-1.60$

4) Calculate the critical value

We need to begin calculating the degrees of freedom

$df=n-1=16-1=15$

The critical value for this case would be :

$P(t_{15}$

The value of a that satisfy this on the normal standard distribution is a=-1.75 and would be the critical value on this case zc=-1.75

5) Calculate the P-value

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}$

6) Conclusion

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3 years ago

HELP!!! 10 points marked brainliest!!!! stuck

nexus9112 [7]

Answer: 43
Explanation: All triangles add up to 180. We can subtract angle Z to get 86. Since X and Y are equal, we can divide 86 by 2.

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3 years ago

A math test has 40 questions. A student answers 85% of the questions correctly. How many questions did the student answer correc

Novosadov [1.4K]

Answer:

Step-by-step explanation:

40 * 0.85 = 34

34 questions answered correctly

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2 years ago

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(Will give Brainliest, these are angle relationships) Please help, and show work, what relationship is it and set up an equation

kozerog [31]

Supplementary angles
x+20+5x+10=180
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3 years ago

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A spring with a spring constant k of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. It is then st

shutvik [7]

Answer:

Equation of movement y(t)

$y(t)=sin(10t-\pi/2)$

Amplitude: 1 inch

Period: 0.628 seconds

Step-by-step explanation:

If there is no friction, the amplitude will be the length it was streched from the equilibrium. In this case, this value is 1 inch

$A=1\,inch$

The period depends on the mass and the spring constant.

The formula for the period is:

$T=\frac{1}{f} =\frac{2/pi}{\omega} =2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{1}{100}}=2\pi*0.1=0.628\, s$

The model y(t) for the movement of the mass-spring system is

$y(t)=A\cdot sin(\omega t +\phi)\\\\A=1\\\\\omega=\sqrt{k/m} =\sqrt{100/1}=10\\\\y(0)=Asin(\phi)=-A\\\\ \phi=arcsin(-1)=-1.571=-\pi/2\\\\\\y(t)=sin(10t-\pi/2)$

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3 years ago