SOLVING QUADRATIC EQUATIONS BY SQUARE ROOT 4m^2-1=-23

2 answers:

7 0

4m^2 -1 = -23 Add 1 to both sides 4m^2 = -22 then divide both sides by 4. m^2 = -11/2. Square root both sides. m = ((square root of 22)/2) times i

PtichkaEL [24]4 years ago

6 0

4m^2-1=-23
⇒ 4m^2= -23+1
⇒ 4m^2= -22
⇒ m^2= -22/4
⇒ m^2= -11/2
⇒ m is undefined for all m∈R (for m^2 is always ≥0 for all m∈R)

Final answer: m is undefined for all m∈R~

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Find the first term and the common ratio third term =6 and seventh term= 96

mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: $a_n= a_1r^{n-1}$

We are given: third term = 6 i,e

$a_3=a_1r(3-1)\\6=a_1r^2----eq(1)$

Seventh term = 96

$a_7=a_1r(7-1)\\96=a_1r^6----eq(2)$

Dividing eq(2) and eq(3)

$\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}$