1 meter is equal to how many feet?

Bananas cost $.65 per pound. Write an equation that can be used to find C, the total cost of P pounds of bananas.

aksik [14]

The equation for this is

$.65p=c

In order to find the total cost we must

have a number in which is multiplied by

$.65.

7 0

3 years ago

What are the positive and negative square roots of 1,6007

Dmitry [639]

Answer: 126.52

Step-by-step explanation:

The square root of 16,007 is approximately 126.52

There are no negative square roots

4 0

3 years ago

What is the difference between bernoulii equation and riccati equation

melisa1 [442]

The Bernoulli equation is almost identical to the standard linear ODE.

$y'=P(x)y+Q(x)y^n$

Compare to the basic linear ODE,

$y'=P(x)y+Q(x)$

Meanwhile, the Riccati equation takes the form

$y'=P(x)+Q(x)y+R(x)y^2$

which in special cases is of Bernoulli type if $P(x)=0$ , and linear if $R(x)=0$ . But in general each type takes a different method to solve. From now on, I'll abbreviate the coefficient functions as $P,Q,R$ for brevity.

For Bernoulli equations, the standard approach is to write

$y'=Py+Qy^n$
$y^{-n}y'=Py^{1-n}+Q$

and substitute $v=y^{1-n}$ . This makes $v'=(1-n)y^{-n}y'$ , so the ODE is rewritten as

$\dfrac1{1-n}v'=Pv+Q$

and the equation is now linear in $v$ .

The Riccati equation, on the other hand, requires a different substitution. Set $v=Ry$ , so that $v'=R'y+Ry'=R'\dfrac vR+Ry'$ . Then you have

$y'=P+Qy+Ry^2$
$\dfrac{v'-R'\dfrac vR}R=P+Q\dfrac vR+R\dfrac{v^2}{R^2}$
$v'=PR+\left(Q+\dfrac{R'}R\right)v+v^2$

Next, setting $v=\dfrac{u'}u$ , so that $v'=\dfrac{uu''-(u')^2}{u^2}$ , allows you to write this as a linear second-order equation. You have

$\dfrac{uu''-(u')^2}{u^2}=PR+\left(Q+\dfrac{R'}R\right)\dfrac{u'}u+\dfrac{(u')^2}{u^2}$
$u''-\left(Q+\dfrac{R'}R\right)u'+PRu=0$
$u''+Su'+Tu=0$

where $S=-\left(Q+\dfrac{R'}R\right)$ and $T=PR$ .

3 0

3 years ago

How to solve algebraic expression using pemas(please excuse my aunt sally)

cupoosta [38]

Its actually PEMDAS you forgot the D.
P-parentheses () E-exponents M-multiplication D-division A-addition S-subtraction. <span />

3 0

3 years ago

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the sum of the two trains is 723.5 mph if the speed of the first train is 12.5 mph faster than that of the second train find the

jonny [76]

First, let's see if we can rewrite this word problem a little bit more mathematically. We won't get to mathy or technical so no worries. We just want to look at it in a more straightforward way, if we can.

Train A's mph plus Train B's mph summed equal 723.5 mph. Train A's mph is greater than Train B's mph by 12.5 mph.
So what should we do to solve this problem? Since we are dealing with two of something and we know the value of the two combined, it might make sense to start by dividing that value by 2.
723.5 / 2 = <em /> 361.75. If the two trains were travelling at the same speed, we would be done. Unfortunately, they are not so we need to think about this some more.
Train A is going 12.5 mph faster than Train B. Let's rewrite.
Train A mph = 12.5 + 361.75 = 374.25 Okay, so Train A is travelling at a speed of 374.25 mph. So we're done right? Not exactly. We are asked to fing the speeds of BOTH trains. How do we find the speed of Train B? We have added a portion of the combined total to Train A. It seems to follow, then, we should probably subtract the same portion from Train A. What are we going to do? You guessed it! Rewrite.
Train B mph = 361.75 - 12.5 = 349.25 HA HA! We seem to have figured it out. Let's do one last thing to check our work. Let's add the two trains' speeds together. If we did this right, we should get our summed value of 723.5 mph
374.25 + 349.25 = 723.5
Pat yourself on the back! We did it!

374.25 + 349.25 =

3 0

3 years ago

Read 2 more answers