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Y_Kistochka [10]
3 years ago
9

Find the value of y. Iog 2 32 =y Ο Ο OC. 6 Ο D. 7

Mathematics
1 answer:
Delicious77 [7]3 years ago
6 0

Answer:

B 5

Step-by-step explanation:

log 2(32)

Replace 32 with 2^5

log2 (2^5)

We know that log a^b = bloga

5 log2(2)

We know that loga(a) =1

5*1

5

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CINDY made costume decorations. She used 1/10 of a meter of ribbon for each decoration which she got by cutting 3/10 of a meter
Brilliant_brown [7]

Answer:

Cindy made 3 decorations with the ribbons

Step-by-step explanation:

Since Cindy used 1/10 of a metre of ribbon to make just one decoration that she obtained by dividing 3/10 of a meter of ribbon into equal parts, then we can calculate the number of decorations that Cindy made. In this scenario, all we need is an idea on how to divide fractions and we are good to go.

If Cindy used 1/10 of a metre obtained by dividing 3/10 of a metre of ribbon to make decorations, then the number of decorations she made can be gotten by dividing 3/10 by 1/10

i.e 3/10 ÷ 1/10

= 3/10 × 10/1

= 3 decorations.

That is she used 1/10 + 1/10 + 1/10 = 3/10 to make (3 decorations).

3 0
3 years ago
Read 2 more answers
Simplify the following fractions<br><br> 8/24<br> 8/32<br> 6/30<br> 12/24<br> 9/21<br> 5/20
Mademuasel [1]

Answer:

for 8/24 the answer will be 1/3.

and for 8/32 the answer will be 1/4.

and for 6/30 the answer will be 1/5.

and for 12/24 the answer will be 1/2.

and for 9/21 the answer will be 3/7.

and for 5/20 the answer will be 1/4

Step-by-step explanation:

4 0
3 years ago
Quadratics formula 4x^2+3x-1=0
VARVARA [1.3K]

Answer: X = 1/4 or X = -1

Step-by-step explanation:

4x2+3x−1=0

(4x−1)(x+1)=0

4x−1=0 or x+1=0

4x=1 or x=-1

Now divide 4 from both sides

like this 4x/4=1/4

now cancel out two 4's so the answer will be x=1/4

3 0
3 years ago
1.2.6 1-118 Find each sum.<br><br> A. 3/5 + 1/3<br><br> B. 5/7 + 1/2<br><br> C. 1/6 + 2/8
Blababa [14]
A.) 14/15 B.) 17/14 C.) 5/12
8 0
3 years ago
I just need 30 please
PIT_PIT [208]

In the smaller triangle, let y be the length of the smallest leg. Then the smallest leg in the larger triangle is 14-y.

Within the scope of the smaller triangle, we have y such that

x^2+y^2=13^2\implies y=\sqrt{13^2-x^2}

Then within the larger the triangle, we would have

x^2+(14-y)^2=15^2\iff x^2+\left(14-\sqrt{13^2-x^2}\right)^2=15^2

Now we can solve for x:

x^2+14^2-28\sqrt{13^2-x^2}+(13^2-x^2)=15^2

\implies x=12

8 0
3 years ago
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