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3 years ago

Find the value of y. Iog 2 32 =y Ο Ο OC. 6 Ο D. 7

Mathematics

1 answer:

Delicious77 [7]3 years ago

6 0

Answer:

B 5

Step-by-step explanation:

log 2(32)

Replace 32 with 2^5

log2 (2^5)

We know that log a^b = bloga

5 log2(2)

We know that loga(a) =1

5*1

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2 years ago

Write an equation for a sine curve that has the given amplitude and period, and which passes through the given point.

Delicious77 [7]

ANSWER

$y = 5\sin( \frac{\pi}{3} x - \frac{2\pi}{3} )$

EXPLANATION

Let the equation of the sine curve be of the form;

$y = a \sin(bx + c)$

where a=5 is the amplitude and period,

$\frac{2\pi}{b} = 6$

This implies that

$b = \frac{2\pi}{6}$

$b = \frac{\pi}{3}$

We substitute the values we got so far into our equation to obtain;

$y = 5\sin( \frac{\pi}{3} x + c)$

When we substitute (2,0) we obtain;

$0= 5\sin( \frac{2\pi}{3} + c)$

Solve for c.

$\sin( \frac{2\pi}{3} + c) = 0$

$\frac{2\pi}{3} + c = \sin^{ - 1} (0)$

$\frac{2\pi}{3} + c = 0$

$c = - \frac{2\pi}{3}$

Hence our equation becomes

$y = 5\sin( \frac{\pi}{3} x - \frac{2\pi}{3} )$

The correct choice is D.

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3 years ago

I need help with a math question but apparently everyone is dead today..

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