Answer:
9(y+3)
Step-by-step explanation:
The way your question is worded, the probability is zero. One ace is not two aces.
<span>let y = sec^2 ( pi x )
y' = 2 sec ( pi x ) sec( pi x ) tan ( pi x ) pi
y' = 2pi sec^2 ( pi x ) tan ( pi x )
y''= 2pi sec^2 ( pi x ) * sec^2 ( pi x ) * pi + 2pi tan ( pi x ) * 2pi sec^2 ( pi x ) tan ( pi x )
y'' = 2 pi^2 sec^4 ( pi x ) + 4 pi^2 sec^2 ( pi x ) tan^2 ( pi x )</span>
Don't mind me, I just need points haha
Answer:
-30(3+2w)
(-9-6w) ⋅ 10
−20(4.5 + 3w)
Step-by-step explanation:
