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charle [14.2K]
3 years ago
14

solution of silver chloride at constant temperature: AgCl(s) ↔ Ag+(aq) + Cl-(aq) As NaCl(s) is dissolved in the solution, the co

ncentration of the Ag+ ions in the solution 1. decreases, and the concentration of Cl- ions increases 2. decreases, and the concentration of Cl- ions remains the same 3. increases, and the concentration of Cl- ions increases 4. increases, and the concentration of Cl- ions remains the same
Chemistry
1 answer:
Grace [21]3 years ago
7 0
As a matter of fact, NaCl(s), when dissolves in water, dissociates into ion Na+ and Cl-.

There is water in the silver chloride solution. Therefore, when being added to the solution, NaCl dissociates into Na+ and Cl-, which makes the concentration of Cl- in the solution increase.

According to Le Chatelier's Principle, when [Cl-] increases, the chemical equation seems to shift in a way that could make more AgCl. Therefore, Ag+ has to react with Cl-, which makes [Ag+] decrease.

The correct answer is (1).

Hope this helps~
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The main purpose of the turbine in the turbojet engine is to A. drive the compressor. B. increase the velocity of the exhaust ga
Naddika [18.5K]
The main purpose of the turbine in the turbojet engine is to drive the compressor.

Answer: A) or the first option.

7 0
4 years ago
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If a sample of HF gas at 694.9 mmHg has a volume of 3.463 Land the volume is changed to 5.887 L, then what will be the new press
VARVARA [1.3K]

Answer:

\large \boxed{\text{381.7 mmHg}}

Explanation:

Data:

p₁ = 694.9 mmHg; V₁ = 3.463 L

p₂ = ?;                     V₂ = 5.887 L

Calculation:

\begin{array}{rcl}p_{1}V_{1} & = & p_{2}V_{2}\\\text{648.9 mmHg} \times \text{3.463 L} & = & p_{2} \times\text{5.887 L}\\\text{2247.1 mmHg} & = & 5.887p_{2}\\p_{2} & = & \dfrac{\text{2247.1 mmHg}}{5.887}\\\\& = &\textbf{381.7 mmHg}\\\end{array}\\\text{The new pressure of the gas is $\large \boxed{\textbf{381.7 mmHg}}$}

4 0
3 years ago
Please help will give brainliest and brainly points tyty <3
Tanya [424]

Answer:

Convection

Explanation:

3 0
3 years ago
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Help plz thanks guys
Fed [463]
Oh no se, aparte que ni inglés se lo siento 0102938
4 0
3 years ago
Consider the reaction of CaC2 and water to produce CaCO3 and NH3 according to the reaction CaCN2 + 3H2O → CaCO3 + 2 NH3 . How mu
xz_007 [3.2K]

Answer:

16.27 g  of CaCO3 are produced upon reaction of 45 g CaCN2 and 45 g of H2O.

Explanation:

Ca(CN)2 + 3H2O → CaCO3 + 2 NH3

First of all, let's find out the limiting reactant.

Molar mass Ca(CN)2.

Molar mass H2O: 18 g/m

Moles of Ca(CN)2: mass / molar mass

45 g / 92.08 g/m = 0.488 moles

Moles of H2O: mass / molar mass

45g / 18g/m = 2.50 moles

This is my rule of three

1 mol of Ca(CN)2 needs 3 moles of H2O

2.5 moles of Ca(CN)2 needs (2.5 . 3) / 1 = 7.5 moles

I need 7.5 moles of water, but I only have 0.488. Obviously water is the limiting reactant; now we can work on it.

3 moles of water __ makes __ 1 mol of CaCO3

0.488 moles of water __ makes ___ (0.488 . 1) / 3 = 0.163 moles

Molar mass CaCO3 = 100.08 g/m

Molar mass . moles = mass

100.08 g/m  .  0.163 moles = 16.27 g

4 0
3 years ago
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