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kirza4 [7]
3 years ago
12

For the balanced equation shown below, how many moles of O2 b

Chemistry
1 answer:
Bas_tet [7]3 years ago
3 0
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In a solution, the solvent In a solution, the solvent can be a liquid or gas. A. is the substance present in the smallest concen
Readme [11.4K]

Answer:

Can either be a solid, a liquid or a gas

Explanation:

A solvent can either be a solid, liquid or a gas. It is the carrier medium in a solution. It is the one in which the solute is dissolved.

Although quite unusual, a solvent might also be a solid. An important application of this can be seen in the production of alloys. Alloys are mixture of metals. To produce let’s say an alloy containing just two metals, the use of a solid solvent is needed. Here, one of the two metals is known as the base metal. It is this base metal that will serve as the carrier medium for the other metal

6 0
3 years ago
How many valence electrons are available for bonding in bromine (Br)?
hichkok12 [17]

Answer:

7

Explanation:

It has 7 typing because it needs to be longer to submit

4 0
3 years ago
You perform a single extraction with 100 mL of chloroform to remove compound A from 100 mL of an aqueous solution. The partition
Mice21 [21]

Answer:

Percentage of mass of solute in aqueous phase is 28.57%.

Explanation:

(q)_{aq}- Fraction of solute in aqueous phase.

(q)_{aq}=\frac{V_{aqueous}}{DV_{organic}+V_{aqueous})}

V_{aqueous} = Used volume of aqueous solution

V_{organic} = Used volume of organic solution

D = partition coefficient.

(q)_{aq}=\frac{100ml}{(2.5\times100)+100\,ml}=0.2857

Mass of solute in aqueous phase = 0.2857\times 5g=1.428g

Mass\,percentage = \frac{1.428}{5.0}\times 100=28.57

Therefore, Percentage of mass of solute in aqueous phase is 28.57%.

5 0
3 years ago
The molar solubility of ba3(po4)2 is 8.89 x 10-9 m in pure water. calculate the ksp for ba3(po4)2. the molar solubility of ba3(p
Flura [38]
Answer is: The molar solubility of ba3(po4)2 is <span>6.00 x 10-39.
</span>Balanced chemical reaction: Ba₃(PO₄)₂(s) → 3Ba²⁺(aq) + 2PO₄³⁻(aq).
s(Ba₃(PO₄)₂) = 8.89·10⁻⁹ M.
[Ba²⁺] = 3s(Ba₃(PO₄)₂) = 3s.
[PO₄³⁻] = 2s.
Ksp = [Ba²⁺]³ · [PO₄³⁻]².
Ksp = (3s)³ · (2s)².
Ksp = 108s⁵.
Ksp = 108·(8.89·10⁻⁹ M)⁵.
Ksp = 108 · 5.55·10⁻⁴¹ = 6·10⁻³⁹.
3 0
3 years ago
Read 2 more answers
How many things do controlled experiments attempt to test at one time? 0 1 3 2
Hunter-Best [27]

Answer:

1

Explanation:

your can only test one thing at a time

5 0
3 years ago
Read 2 more answers
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