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kirza4 [7]
3 years ago
12

For the balanced equation shown below, how many moles of O2 b

Chemistry
1 answer:
Bas_tet [7]3 years ago
3 0
Download the app “Socratic” it will give you answers to all u need to know about all subjects.
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Amalgam is an alloy that contains mercury and other metals. Which of these atoms would most likely form metallic bonds with merc
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I would say copper, silver, and tin, since an alloy is a mixture of metals and metalloids.
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Read 2 more answers
PLEASE HELP ILL MARK BRAINLEST
ziro4ka [17]

Answer:

Answer:

0.35

0.91

1.26

1.57

Explanation:

did it on edge

8 0
3 years ago
Calculate the work associated with the compression of a gas from 121.0 l to 80.0 l at a constant pressure of 16.7 atm.
Molodets [167]
I’m am most positive the answer is c. For cat
6 0
3 years ago
What is the frequency and energy per quantum (in Joules) of :
viktelen [127]

(a) f = 5.00 × 10²⁰ Hz, E = 3.32 × 10⁻¹³ J;

(b) f = 1.20 × 10¹⁰ Hz, E = 7.96 × 10⁻²⁴J.

<h3>Explanation</h3>

What's the similarity between a gamma ray and a microwave?

Both gamma rays and microwave rays are electromagnetic radiations. Both travel at the speed of light at 3.00 \times 10^{8}\;\text{m}\cdot\text{s}^{-1} in vacuum.

f = \dfrac{c}{\lambda}

where

  • f is the frequency of the electromagnetic radiation,
  • c is the speed of light, and
  • \lambda is the wavelength of the radiation.

(a)

Convert all units to standard ones.

\lambda = 0.600\;\text{pm} = 0.600 \times 10^{-12} \;\text{m}.

The unit of f shall also be standard.

f = \dfrac{c}{\lambda} = \dfrac{3.00\times 10^{8}\;\text{m}\cdot\text{s}^{-1}}{0.600\times 10^{12}\;\text{m}} = 5.00 \times 10^{20}\;\text{s}^{-1}= 5.00\times 10^{20}\;\text{Hz}.

For each particle,

E = h\cdot f,

where

  • E is the energy of the particle,
  • h is the planck's constant where h = 6.63\times 10^{-34}\;\text{J}\cdot\text{s}^{-1}, and
  • f is the frequency of the particle.

E = h \cdot f = 6.63\times10^{-34}\;\text{J}\cdot\text{s}\times 5.00\times 10^{20}\;\text{s}^{-1} = 3.32\times10^{-13}\;\text{J}.

(b)

Try the steps in (a) for this beam of microwave with

  • \lambda = 2.50 \;\text{cm} = 2.50\times 10^{-2}\;\text{m}.

Expect the following results:

  • f = 1.20\times 10^{10}\;\text{Hz}, and
  • E = 7.96\times 10^{-24}\;\text{J}.
4 0
3 years ago
A 200.0 mL solution of 0.40 M ammonium chloride was titrated with 0.80 M sodium hydroxide. What was the pH of the solution after
Rus_ich [418]

Answer:

pH = 9.25

Explanation:

Step 1: Data given

Volume of a 0.40 M NH4Cl solution = 200.0 mL = 0.200 L

Molarity of NaOH = 0.80 M

Volume of NaOH = 50.0 mL

The Kb of ammonia is 1.76×10^-5

Step 2: The balanced equation

NH4Cl + NaOH → NH3 + NaCl + H2O

Step 3: Calculate moles

Moles NH4Cl  = molarity *¨volume

Moles NH4Cl = 0.40 M * 0.200 L = 0.08 moles

Moles NaOH = 0.80 M * 0.050 L = 0.04 moles

Step 4: Calculate limiting reactant

NaOH will completely be consumed. (0.04 moles). NH44Cl is in excess. There will react 0.04 moles .there will remain 0.04 moles.

Step 5: Calculate moles NH3

Moles NH3 = for 0.4 moles NH4Cl we'll have 0.4 moles NH3

Step 6: Calculate molarity

Molarity = moles / volume

Molarity = 0.4 moles = 0.250 L

Molarity = 1.6 M

Step 7: Calculate pOH

pOH = pKb + log ([B+]/[BOH])

pOH = 4.75 + log (1.6 / 1.6)

pOH = 4.75

Step 8: Calculate pH

pH = 14 - 4.75

pH = 9.25

3 0
3 years ago
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