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jasenka [17]
3 years ago
6

Find an equation of the line passing through the given points. Use function notation to write the equation. (-3,11) and (0,2)

Mathematics
2 answers:
Natali [406]3 years ago
8 0

\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{11})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-11}{0-(-3)}\implies \cfrac{-9}{0+3}\implies \cfrac{-9}{3}\implies -3 \\\\\\


\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-11=-3[x-(-3)]\implies y-11=-3(x+3) \\\\\\ y-11=-3x-9\implies y=-3x+2\implies \stackrel{\textit{using function notation}}{f(x)=-3x+2}

juin [17]3 years ago
6 0

Answer:

y=-3x+2

Step-by-step explanation:


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Marina86 [1]

Answer:

I think its D

Step-by-step explanation

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5 0
2 years ago
A math class is having a discussion on how to determine if the expressions 4x-x+5 and 8-3x-3 are equivalent using
Mkey [24]

Answer:

  Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are the same, then the two expressions must be equivalent.

Step-by-step explanation:

Both expressions are linear expressions. It takes 2 points to define a line. If the lines defined by each expression go through the same two points, then the expressions are equivalent.

If the expressions have the same value for two different variable values, they are equivalent. (choice D)

_____

<em>Additional comment</em>

One more point is needed than the degree of the polynomial expression. That is, quadratic (degree 2) expressions will be equivalent if they go through the same 2+1 = 3 points.

6 0
3 years ago
What is the equation of the line that passes through the point (-1,7) and has a slope of -2?
Pani-rosa [81]
Y = -2x + b
Plug in the point
7 = -2(-1) + b
7 = 2 + b
b = 5
Final equation y = -2x + 5
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3 years ago
Press on the picture
scoray [572]
B is the correct answer
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3 years ago
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Please help &lt;3 Thanks!!
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