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ladessa [460]
4 years ago
11

PLEASE i AM CRYING RIGHT NOW I HAVE HAD NO SLEEP AND I DONT KNOW THE ANSWER PLEASE

Mathematics
1 answer:
MAVERICK [17]4 years ago
4 0

c = number of children tickets sold

a = number of adult tickets sold.


we know that 178 total tickets were sold, thus whatever "c" and "a" are, c + a = 178.

the price of a child ticket is $5.4, so the price for all "c" tickets must be 5.4c.

the price of a adult ticket is $9, so the price for all "a" tickets must be ac.

we also know the total sales for all tickets combined is $1310.4, so then 5.4c + 9a = 1310.4.


\bf \begin{cases} c+a=178\implies \boxed{c}=178-c\\ 5.4c+9a=1310.4\\[-0.5em] \hrulefill\\ 5.4c+9\left( \boxed{178-c} \right)=1310.4 \end{cases} \\\\\\ 5.4c+1602-9c=1310.4\implies -3.6c+1602=1310.4\implies -3.6c=-291.6 \\\\\\ c=\cfrac{-291.6}{3.6}\implies c=81

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Answer:

C

Step-by-step explanation:

Asymptote is basically a line that the graph approaches but NEVER cuts/crosses.

<em><u>Remember, x = a where a is a constant is an equation of a vertical line and x = b, where b is a constant, is the equation of a horizontal line.</u></em>

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  • Looking at the graph, we can see that the curve doesn't cross an imaginary line at  x = 0, this is a vertical asymptote.
  • Also, we can see that the curve doesn't cross an imaginary line at y = -2, this is a horizontal asymptote.

Looking at the answer choices, the choice C is right.

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18 acres / 6 days = 3 acres per day.

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Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)
lisov135 [29]

Answer:

(a) The system of the equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. has no solution.

(b) The system of the equations \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. has many solutions y=\frac{2x}{3}-\frac{5}{3}

Step-by-step explanation:

(a) To find the solutions of the following system of equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. you must:

Multiply 2x-3y=3 by 2:

\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}

Subtract the equations

4x-6y=3\\-\\4x-6y=6\\------\\0=-3

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. you must:

Isolate x for 4x-6y=10

x=\frac{5+3y}{2}

Substitute x=\frac{5+3y}{2} into the second equation

16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40

The system has many solutions.

Isolate y for 4x-6y=10

y=\frac{2x}{3}-\frac{5}{3}

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3 years ago
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