Since it is a geometric sequence each term will be a specific multiple of the term preceding it, called the common ratio...
126/42=378/126=1134/378=3
The sequence is a(n)=a(3)^(n-1) and we know the second term is 42 so:
42=a(3)^(2-1)
42=3a
a=14
So the first term is 14.
The answer is -10x^3+23x^2-24x+18
Answer:
The answer is 6.5 hours.
Step-by-step explanation:
If you multiply the hours need to work during that week days(6) and the hours worked during the weekend(3.5) you get 33.5 hours worked over all. then, you subtract 40(the hours wanted) and 33.5(the hours worked normally) and you get 6.5.
