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madam [21]
4 years ago
14

HELP ME AS SOON AS POSSIBLE

Mathematics
2 answers:
IgorC [24]4 years ago
6 0

Answer:

50

Step-by-step explanation:

It ain't that hard. You just have to be careful and take things slow.... Here's how we can work it out:

\frac{ {8}^{ \frac{1}{3} } }{ {5}^{ - 2} }  =  \frac{ \sqrt[3]{ {8}^{1} } }{ \frac{1}{ {5}^{2} } }  =  \frac{ \sqrt[3]{ {2}^{3} } }{ \frac{1}{ {5}^{2} } }  =  \frac{2}{ \frac{1}{25} }  =  2 \times 25 = 50

I've used a couple things.

{8}^{ \frac{a}{b} }  =  \sqrt[b]{ {8}^{a} }

{5}^{ - a}  =  \frac{1}{ {5}^{a} }

and...

\frac{ \frac{a}{b} }{ \frac{c}{d} }  =  \frac{ad}{bc}

In other words,

\frac{2}{ \frac{1}{25} }  =  \frac{ \frac{2}{1} }{ \frac{1}{25} }  =  \frac{2 \times 25}{1 \times 1}  = 2 \times 25 = 50

Hope I've helped ;)

iris [78.8K]4 years ago
3 0
(8 1/3 / 5) - 2 = -0.333333333

i hope this helps
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Answer:

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Step-by-step explanation:

Given:

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150 =tan^{-1}(\frac{y}{x} )\\\frac{y}{x} =tan 150\\\frac{y}{x}=-\frac{\sqrt{3} }{3}

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144=x^2+(-\frac{x \sqrt{3}}{3} )^2\\144=x^2+\frac{3x^2}{9} \\144=\frac{4x^2}{3}\\4x^2=144 X 3=432\\x^2=108\\x=6\sqrt{3}

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Step-by-step explanation:

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Ali finished his history assignment in 1/4
Lina20 [59]
Hello there!

For this you simply need to give both fractions a common denominator!

The easiest way to do this specific problem would be to make the denominator 12. Why 12? Because 4 x 3 = 12.

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Notice how the denominator stayed the same? When adding/subtracting fractions, the denominator stays the same! :)

Hope this helped!

-------------------------------

DISCLAIMER: I am not a professional tutor or have any professional background in your subject. Please do not copy my work down, as that will only make things harder for you in the long run. Take the time to really understand this, and it'll make future problems easier. I am human, and may make mistakes, despite my best efforts. Again, I possess no professional background in your subject, so anything you do with my help will be your responsibility. Thank you for reading this, and have a wonderful day/night!
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