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Vikki [24]
3 years ago
11

An FM radio station broadcasts at 98 MHz. what is the energy of each photon in Joule? Use h= 6.6 X10^-34 J*s for Planck constant

.
Mathematics
1 answer:
jenyasd209 [6]3 years ago
8 0

Answer:

Energy of each photon will be 6.468\times 10^{-24}J

Step-by-step explanation:

We have given frequency \nu = 98 MHz =98\times 10^6Hz

We have given plank's constant h=6.6\times 10^{-34}j-s

We have to find the energy of each photon

Energy of photon is given by E=h\nu, here h is plank's constant and \nu is frequency

So energy E=6.6\times 10^{-34}\times 98\times 10^6=6.468\times 10^{-24}J

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