Question

An FM radio station broadcasts at 98 MHz. what is the energy of each photon in Joule? Use h= 6.6 X10^-34 J*s for Planck constant.

Answer 1

Answer:

Energy of each photon will be $6.468\times 10^{-24}J$

Step-by-step explanation:

We have given frequency $\nu$ = 98 MHz $=98\times 10^6Hz$

We have given plank's constant $h=6.6\times 10^{-34}j-s$

We have to find the energy of each photon

Energy of photon is given by $E=h\nu$, here h is plank's constant and $\nu$ is frequency

So energy $E=6.6\times 10^{-34}\times 98\times 10^6=6.468\times 10^{-24}J$