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tiny-mole [99]
3 years ago
15

What is the estimated difference? Round each number to the nearest ten thousand before finding the difference. 6,609,707 – 147,7

79
Mathematics
1 answer:
jok3333 [9.3K]3 years ago
7 0
6,610,000-150,000= 6,460,000
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Help with this problem please !!!!!
Karolina [17]

Answer:

28

Step-by-step explanation:

Cross multiply

18k = 12 x 42

18 k = 504

   k = 504/18

   k = 28

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3 years ago
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9. One winter day, the temperature increased
Andru [333]

Answer: A~ 45

Step-by-step explanation:

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3 years ago
Which interval for the graphed function contains the local maximum?
photoshop1234 [79]

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2

Step-by-step explanation:

5 0
3 years ago
Solution for dy/dx+xsin 2 y=x^3 cos^2y
vichka [17]
Rearrange the ODE as

\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y=x^3\cos^2y
\sec^2y\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y\sec^2y=x^3

Take u=\tan y, so that \dfrac{\mathrm du}{\mathrm dx}=\sec^2y\dfrac{\mathrm dy}{\mathrm dx}.

Supposing that |y|, we have \tan^{-1}u=y, from which it follows that

\sin2y=2\sin y\cos y=2\dfrac u{\sqrt{u^2+1}}\dfrac1{\sqrt{u^2+1}}=\dfrac{2u}{u^2+1}
\sec^2y=1+\tan^2y=1+u^2

So we can write the ODE as

\dfrac{\mathrm du}{\mathrm dx}+2xu=x^3

which is linear in u. Multiplying both sides by e^{x^2}, we have

e^{x^2}\dfrac{\mathrm du}{\mathrm dx}+2xe^{x^2}u=x^3e^{x^2}
\dfrac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]=x^3e^{x^2}

Integrate both sides with respect to x:

\displaystyle\int\frac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]\,\mathrm dx=\int x^3e^{x^2}\,\mathrm dx
e^{x^2}u=\displaystyle\int x^3e^{x^2}\,\mathrm dx

Substitute t=x^2, so that \mathrm dt=2x\,\mathrm dx. Then

\displaystyle\int x^3e^{x^2}\,\mathrm dx=\frac12\int 2xx^2e^{x^2}\,\mathrm dx=\frac12\int te^t\,\mathrm dt

Integrate the right hand side by parts using

f=t\implies\mathrm df=\mathrm dt
\mathrm dg=e^t\,\mathrm dt\implies g=e^t
\displaystyle\frac12\int te^t\,\mathrm dt=\frac12\left(te^t-\int e^t\,\mathrm dt\right)

You should end up with

e^{x^2}u=\dfrac12e^{x^2}(x^2-1)+C
u=\dfrac{x^2-1}2+Ce^{-x^2}
\tan y=\dfrac{x^2-1}2+Ce^{-x^2}

and provided that we restrict |y|, we can write

y=\tan^{-1}\left(\dfrac{x^2-1}2+Ce^{-x^2}\right)
5 0
3 years ago
Cara is a high school student. On average, there are 26 students per class at her school, with a standard deviation of 3 student
aliina [53]

Answer:

B. 97%

Step-by-step explanation:

20 students is -2 standard deviations away from the mean

35 is +3 standard deviations away from the mean

100 - 2.4 = 97.6

(2.4 is amount of data we are not using)

please refer to the standard deviation graph attached :)

8 0
2 years ago
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