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Fittoniya [83]
3 years ago
9

Use simple interest to find the interest and ending balance

Mathematics
1 answer:
hammer [34]3 years ago
7 0

Answer:

Interest = $240

Ending Balance = $990

Step-by-step explanation:

Applying I = prt/100

= (750*4*8)/100

= 240

Therefore Interest = $240

Adding Interest to Principal

= $240 + $750 = $990

=

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What is the result of 96 divided by 6?8 12 16 or 32
hram777 [196]
96 divided by 6 is 16

96 divided by 8 is 12

96 divided by 12 is 8

96 divided by 16 is 6

96 divided by 32 is 3
8 0
3 years ago
Read 2 more answers
The sum of ages Afful and Naomi is 34. In 5 years time , Afful will be 2 times the age on Naomi now. How old are they now.
GenaCL600 [577]

Answer:

Afful is 21 and Naomi is 13.

Step-by-step explanation:

Let A represent the age of Afful and N represent the age of Naomi.

The sum of their ages is 34. In other words:

A+N=34

In 5 years time, Afful will be two times the age of Naomi <em>now</em>. In other words:

A+5=2N

Solve for the system. Substitute.

A+N=34\\A=34-N\\34-N+5=2N\\39=3N\\N=13\\\\A=34-N\\A=34-(13)\\A=21

Afful is currently 21 and Noami is currently 13.

7 0
3 years ago
Read 2 more answers
admission to a carnival is $5 and each game at the carnival cost $0.85. you have $15 to spend on admission and games. what is th
aleksandrvk [35]
So, you have $15 in total to spend.

1. Subtract your admission fee. 15-5=10
2. Divide 10 by .85 to get the number of games you were able to play. 10 divided by .85 = 11.76
3. Now, since it says the minimum you were able to play, round to the nearest digit. 11.76=11

You were able to play a minimum of 1 game and a maximum of 11 games.
7 0
3 years ago
HURRY HELP QUICK
LuckyWell [14K]

Answer:

m is greater than or equal to -1, m is less than or equal to -10

Step-by-step explanation:

-1+-10

6 0
3 years ago
Show that if a and b are positive integers, then ab = gcd (a, b). lcm (a, b) . [Hint: Use prime factorizations of a and b and th
AleksandrR [38]

Answer:

ab=\gcd(a,b)\cdot \text{lcm}(a,b)

Step-by-step explanation:

Using the hint, write a and b in the following prime factorization:

a=p_1^{x_1}p_2^{x_2}\cdots p_t^{x_t}\cdot q,

b=p_1^{y_1}p_2^{y_2}\cdots p_t^{y_t}\cdot r,

where  \gcd(p_i,r)=1,\ \gcd(p_i,q)=1,\ \gcd(r,q)=1,\ \gcd(p_i,p_j)=1, for i ≠ j.

Then by the formulae for gcd(a,b) and lcm(a,b) we know that:

\gcd(a,b)=p_1^{\min(x_1,y_1)}p_2^{\min (x_2,y_2)} \cdots p_t^{\min(x_t,y_t)}

\text{lcm}(a,b)= q\cdot r\cdot p_1^{\max(x_1,y_1)}p_2^{\max(x_2,y_2)}\cdots p_t^{\max(x_t,y_t)}

Note that the expression \min(x_i,y_i)+\max(x_i,y_i)=x_i+y_i for all i, since if the minimum is, <em>without loss of generality</em>, x_i, then the maximum must be y_i, and viceversa. Then, it is straightforward to verify that when we multiply gcd(a, b) and lcm(a, b) its prime factorization matches the prime factorization of ab, and so we can see the equaility holds:

\gcd(a,b)\cdot \text{lcm}(a,b)=ab.

7 0
3 years ago
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