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docker41 [41]
2 years ago
6

What does m represent in the equation y= mx+b? Iready

Mathematics
1 answer:
zysi [14]2 years ago
6 0

Answer:

"m" represents the slope in the linear equation, <em>y = mx + b</em>

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Which of the following equations has only one solution? x2 + 4x + 4 = 0 x2 + x = 0 x2 - 1 = 0
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A circular plot of land has a diameter of 16 yards. What is the area of theland? Use 3.14 for it.O A. 803.84 yd2O B. 50.24 yd2O
Amiraneli [1.4K]

The area of the circle can be calculated with the following formula

A=\pi\cdot r^2

First let's find the radius

\begin{gathered} r=\frac{16}{2}\text{yds} \\ r=8\text{yds} \end{gathered}\begin{gathered} A=\pi\cdot8^2 \\ A=3.14\cdot64 \\ A=200.96\text{ yd2} \end{gathered}

The answer would be 200.96 square yards

6 0
1 year ago
Sara and Tatiana both buy ice cream over the weekend. Sara goes to the corner store and buys 7 pints of ice cream for $20 .Tatia
HACTEHA [7]

Answer:


Step-by-step explanation:

There are 2 cups in 1 pint.

Sara gets 2 * 7 = 14 cups

She pays 20 dollars.

Tatiana buys 15 1/2 cups for 20 dollars. In effect, Tatiana got 1.5 cups free, so she got the better deal.

3 0
3 years ago
Use Newton's method to find the second and third approximation of a root of x3+x+2=0 starting with x1=−1 as the initial approxim
adoni [48]

Answer:

The third approximation is x_3=-1.08259

Step-by-step explanation:

We are given that  

f(x)=x^3+x+2=0

x_1=-2

We have to find the second and third approximation of a root of given equation by using Newton's method.

We know that Newton's method , if nth approximation is given x_n and f'(x_n)\neq 0 then, the next approximation is given by  

x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}

f'(x)=3x^2+1

Substitute x_1=-2

f(x_1)=f(-2)=(-2)^3+(-2)+2=-8

f'(x_1)=f'(-2)=3(-2)^2+1=13

Substitute the value n=1 then, we get  

x_2=x_1-\frac{f(x_1)}{f'(x_1)}

Substitute the values then , we get  the second approximation

x_2=-2-\frac{-8}{13}=-\frac{18}{13}

For n=2

f(x_2)=f(-\frac{18}{13})=(-\frac{18}{13})^3-\frac{18}{13}+2=-2.03914

f'(x_2)=f'(-\frac{18}{13})=3(-\frac{18}{13})^2+1=6.75148

x_3=x_2-\frac{f(x_2)}{f'(x_2)}

x_3=-\frac{18}{13}-\frac{-2.03914}{6.75148}=-1.08259

Hence, the third approximation is x_3=-1.08259

7 0
3 years ago
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