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klemol [59]
3 years ago
15

What is the solution of the system equations y =-3x +8 y = -5x -2

Mathematics
1 answer:
Talja [164]3 years ago
8 0

Answer:

Since both equations are equal to y, we can set them equal to each other.

y =-3x +8

y = -5x -2

-3x +8 = -5x -2

Solve for x.To do this, we need to get x by itself. First, move all the numbers to one side of the equation, and all the variables to the other.

-3x +8 = -5x -2

Add 5x to both sides

-3x+5x +8=-5x+5x -2

2x+8=-2

Subtract 8 from both sides

2x+8-8 = -2-8

2x=-10

Now, all the numbers are on one side, with the variables on the other. x is not by itself, it is being multiplied by 2. To undo this, divide both sides by 2

2x/2= -10/2

x= -5

Now, to find y, substitute -5 in for x in one of the equations.

y = -5x -2

y= -5(-5) -2

y=25-2

y=23

Put the solution into (x,y)

<u><em>The solution is (-5, 23)</em></u>

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Vesna [10]

Answer:

The equivalent expression is:

16x^4-81=(4x^2-9)(4x^2+9)

Step-by-step explanation:

We have been given the equation:

f(x)=16x^4-81=0

Equivalent expression can be computed by solving the expression ai its maximum.

We can factorize the given equation:

By using a^2-b^2=(a+b)(a-b)

Here, a=4x^2,b=9

Hence, we get the equation below:

16x^4-81=(4x^2-9)(4x^2+9)

Therefore, the equivalent expression is:

16x^4-81=(4x^2-9)(4x^2+9)

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Answer:

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Step-by-step explanation:

As with many geometry problems, there are several ways you can work this.

Label the lower left  and lower right vertices of the rectangle points W and E, respectively. You can subtract the areas of triangles WSR and EQR from the area of trapezoid WSQE to find the area of triangle QRS.

The applicable formulas are ...

  area of a trapezoid: A = (1/2)(b1 +b2)h

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So, our areas are ...

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Factoring out 1/2, we have ...

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Step-by-step explanation:

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Step-by-step explanation:

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