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alukav5142 [94]

3 years ago

8

You use the associative property of multiplication to change how factors

1 answer:

White raven [17]3 years ago

5 0

Answer:

do you have to show work?

Step-by-step explanation:

i will show work if its needed

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I need help with this one plz! (marking BRAINLIST) :)

miskamm [114]

Answer: (a) = 110 degrees, (b) = 8

If I understand the picture correctly, (a) wants you to find the angle K. It first shows us that both J to K, and L to K are equal in length of 11, thus there is no deviation in angle 35 degrees with L (so they both equal each other). Therefore, the angle K will equal 180 degrees subtracted by the sum of J and L, which is 110 degrees.

For (b), it appears that all the angles have the same singular mark at the edges, so all sides will equal 8.

I hope this helped!

3 0

3 years ago

Does anybody no what is 19+9 is?

Licemer1 [7]

28

step by step
19+9=28

5 0

3 years ago

Read 2 more answers

If there are 21 values in a data set in order from smallest to largest, what is the third quartile of the data set?

WARRIOR [948]

Answer:

,m

Step-by-step explanation:

3 0

3 years ago

Nutka1998 [239]

Answer:

$m\angle MEJ=25^{\circ}.$

Step-by-step explanation:

The arcs LY, KM, KL and MJ together form the full revolution angle, thus

$4x+50^{\circ}+6x+x+10^{\circ}+4x=360^{\circ},\\ \\15x=300^{\circ},\\ \\x=20^{\circ}.$

Note that

$m\angle MOJ=4x=80^{\circ},$

then

$m\angle MLJ=\dfrac{1}{2}\cdot 80^{\circ}=40^{\circ}.$

So,

$m\angle ELM=180^{\circ}-40^{\circ}=140^{\circ}.$

Also

$m\angle LOK=30^{\circ},$

so

$m\angle KML=\dfrac{1}{2}\cdot 30^{\circ}=15^{\circ}.$

In triangle EML,

$m\angle MEL+m\angle EML+m\angle ELM=180^{\circ},\\ \\m\angle MEL=180^{\circ}-15^{\circ}-140^{\circ}=25^{\circ}.$

Thus, $m\angle MEJ=25^{\circ}.$

7 0

4 years ago

Use the definition of continuity and the properties of limits to show that the function

Zepler [3.9K]

Answer:

Applied the definition and the limit.

They had the same result, so the function is continuous.

Step-by-step explanation:

At function f(x) is continuous at x = a if:

$\lim_{x \to a} f(x) = f(a)$

In this question:

$f(x) = x^{2} + 5(x-2)^{7}$

At x = 3.

$\lim_{x \to 3} x^{2} + 5(x-2)^{7} = 3^{2} + 5(3-2)^{7} = 14$

$f(3) = 3^{2} + 5(3-2)^{7} = 14$

Since $\lim_{x \to 3} f(x) = f(3)$ , f(x) is continuous at x = 3.

7 0

3 years ago