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Ainat [17]
3 years ago
10

Which statement could be used to explain why f(x) = 2x – 3 has an inverse relation that is a function? The graph of f(x) passes

the vertical line test. f(x) is a one-to-one function. The graph of the inverse of f(x) passes the horizontal line test. f(x) is not a function.

Mathematics
2 answers:
alina1380 [7]3 years ago
7 0

Answer:

f(x) is a one to one function.That maps out one function to another ,and it therefore passes both the vertical and horizontal I ine test



antiseptic1488 [7]3 years ago
7 0

Answer with explanation:

The given linear function is

    f(x)= 2 x -3

y=2 x -3

y+3=2x\\\\x=\frac{y+3}{2}

Replacing , x by y, and y by x, we will get the Inverse of the given function

y=\frac{x+3}{2}

Since ,for every x, there is a unique y, or for every, y there is unique x, therefore it is a function.

We can check this also by using the concept of function, that is the function must be one one and Onto.

To check whether, the linear function is one- one,

If ,f(a)=f(b), then , a=b.

f(a)= 2 a -3

f(b)=2 b -3

2 a -3 = 2 b -3

2 a= 2 b

a=b

So, f(x)=2 x -3, is one -one.

To Check whether it is onto

for, f(x)=y

there must be unique x, for unique y

y=\frac{x+3}{2}

So , f(x) is one one and onto.Which shows that f(x) has an Inverse.

Otherwise , we will use Horizontal line test.

Draw the graph of , f(x)=2 x -3

Horizontal lines does not cut the function, more than once.

or, you can find the inverse of f(x),then check whether it passes Horizontal line test.That is, function , 2 y = x +3, the inverse function Passes Horizontal Line test.

Option C: The graph of the inverse of f(x) passes the horizontal line test.

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Answer:

i = 77.5°

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RANDOMLY CHOOSING TWO POTENTIAL CLIENTS
gregori [183]
Let <span>Jacob, Carol, Geraldo, Meg, Earvin, Dora, Adam, and Sally be represented by the letters J, C, G, M, E, D, A, and S respectively. </span>

<span>In part IV we are asked:

</span><span>What is the sample space of the pairs of potential clients that could be chosen?
</span><span>
Since the Sample Space is the set of all possible outcomes, we need to make a set (a list) of all the possible pairs, which are as follows:

{(J, C), (J, G), (J, M), (J, E), (J, D), (J, A), (J, S)

          , </span>(C, G), (C, M), (C, E), (C, D), (C, A), (C, S)
<span>                   
</span>                      , (G, M), (G, E), (G, D), (G, A), (G, S)
<span>             
                                    ,</span>(M, E), (M, D), (M, A), (M, S)    
<span> 
                                               , </span>(E, D),  (E, A),  (E, S) <span>   
                                                          
                                                           , </span>(D, A), (D, S)
              
                                                                       , (A, S).}

We can check that the number of the elements of the sample space, n(S) is 

1+2+3+4+5+6+7=28.


This gives us the answer to the first question: <span>How many pairs of potential clients can be randomly chosen from the pool of eight candidates? 

(Answer: 28.)


II) </span><span>What is the probability of any particular pair being chosen?
</span>
The probability of a particular pair to be picked is 1/28, as there is only one way of choosing a particular pair, out of 28 possible pairs.

III) <span>What is the probability that the pair chosen is Jacob and Meg or Geraldo and Sally? 

The probability of choosing (J, M) or (G, S) is 2 out of 28, that is 1/14.


Answers:

I) 28
II) 1/28</span>≈0.0357
III) 1/14≈0.0714
IV)


{(J, C),  (J, G), (J, M),  (J, E),   (J, D),  (J, A),   (J, S)
          , (C, G), (C, M), (C, E),   (C, D), (C, A),  (C, S)
                      , (G, M), (G, E),  (G, D), (G, A),  (G, S)
                                   ,(M, E),  (M, D), (M, A),  (M, S)    
                                               , (E, D),  (E, A),  (E, S)    
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                                                                        , (A, S).}
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