Direction vector of line of intersection of two planes is the cross product of the normal vectors of the planes, namely
p1: x+y+z=2
p2: x+7y+7z=2
and the corresponding normal vectors are: (equiv. to coeff. of the plane)
n1:<1,1,1>
n2:<1,7,7>
The cross product n1 x n2
vl=
i j l
1 1 1
1 7 7
=<7-7, 1-7, 7-1>
=<0,-6,6>
Simplify by reducing length by a factor of 6
vl=<0,-1,1>
By observing the equations of the two planes, we see that (2,0,0) is a point on the intersection, because this points satisfies both plane equations.
Thus the parametric equation of the line is
L: (2,0,0)+t(0,-1,1)
or
L: x=2, y=-t, z=t
With one point of the compass on the vertex of the angle, draw an arc that intersects both sides of the angle. Draw an arc from each of these points of intersection so that the arcs intersect<span> in the interior of the angle. The compass needs to </span>stay open<span> the same amount throughout this step.
I hoped that help..have a great day:)
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Answer:
Step-by-step explanation:
So we have:
And we want to solve for π.
First, divide both sides by h:
Now, divide both sides again by r²:
And this is our answer :)
