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Effectus [21]
3 years ago
10

I need a lot of help What is 89/2?

Mathematics
2 answers:
bekas [8.4K]3 years ago
7 0

Answer:

44.5

is the answer

Rzqust [24]3 years ago
6 0

Answer:

As a decimal 44.5 as a mixed number 44 1/2

Step-by-step explanation:

Plzzz mark me brainliest?

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Let f(x)=cos(x)x^-2<br> F’(x)=
kondaur [170]

f(x)=cos(x)x^{-2}\implies f(x)=\cfrac{cos(x)}{x^2}\implies \cfrac{df}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{-sin(x)\cdot x^2-cos(x)\cdot 2x}{(x^2)^2}} \\\\\\ \cfrac{df}{dx}=\cfrac{-x[x\cdot sin(x)+2cos(x)]}{x^4}\implies \cfrac{df}{dx}=\cfrac{-[xsin(x)+2cos(x)]}{x^3}

8 0
2 years ago
A culture started with 5,000 bacteria. After 2 hours, it grew to 6,500 bacteria. Predict how many bacteria will be present after
lesya [120]
This can be expressed as exponential growth of the form:

f=ir^t, f=final amount, i=initial amount, r=common ratio (rate), t=time

In this case we are given the point (2, 6500) and i=5000 so we can solve for the rate...

6500=5000r^2  divide both sides by 5000

1.3=r^2  take the square root of both sides and note that we know r>0

r=1.3^(1/2) so our equation becomes:

f=5000(1.3)^(1/2)^t  and knowing that (a^b)^c=a^(b*c) we can say:

f=5000(1.3)^(t/2)  so for t=18

f=5000(1.3)^9

f≈53022  (to nearest whole bacteria)
7 0
3 years ago
A snail traveled 150 feet per hour. How far would he travel in 45 minutes?
Nuetrik [128]

Answer:

112.5 which is 113

Step-by-step explanation:

150 divided by 60= 2.5

2.5 times 45=112.5

3 0
3 years ago
what is the equation to seven less than the product of twice a number is greater than 5 more than the same number
postnew [5]
<span>seven less than (-7) than the product of twice a number (2x) is greater than (>) five more than (+5) the same number (x)

2x-7>x+5
treat the > sign as an equals for now
2x-7=x+5
subtract x from both sides
x-7=5
add 7 to both sides
x=12
put the > sign back in
x>12</span>
7 0
4 years ago
Read 2 more answers
How to integrate ∫㏑x/χ<br> from 1 to e
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\int_1^e\dfrac{\ln x}{x}dx,~\text{if}~u=\ln x\to x=e^u\to dx=e^udu\\\\\text{So, finding the new limits:}\begin{cases}x=1\to u=\ln1\to u=0\\x=e\to u=\ln e\to u=1\end{cases}\\\\&#10;\int_1^e\dfrac{\ln x}{x}dx=\int_0^1\dfrac{u}{e^u}e^udu=\int_0^1u\,du=\left[\dfrac{u^2}{2}\right]_0^1=\dfrac{1^2}{2}-\dfrac{0^2}{2}=\dfrac{1}{2}\\\\&#10;\boxed{\int_1^e\dfrac{\ln x}{x}dx=\dfrac{1}{2}}
6 0
3 years ago
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