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Inga [223]
3 years ago
13

Find the difference of the complex numbers.

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
6 0

Answer:

  D.  7 +11i

Step-by-step explanation:

In many situations, you can treat "i" as though it were a variable. Collect terms in the usual way.

  (2 +8i) -(-5-3i) = 2 +8i +5 +3i = (2+5) +(8+3)i

  = 7 +11i

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Kent is making a scale model of his favorite train. The actual train is 12 feet long and 4 feet wide. Kent wants his model to be 6 inches in length. Which would if he uses the same ratio?

Step-by-step explanation:

Kent is making a scale model of his favorite train. The actual train is 12 feet long and 4 feet wide. Kent wants his model to be 6 inches in length. Which would be the width if he uses the same ratio?

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A$250 suit is marked down by 30%. Find the sale price,
Dahasolnce [82]

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175 is the answer the percentage is 75

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slant height of a right cone is 5 inches, and radius of its base is 3 inches, what is the lateral area?
Alik [6]
*Hint: The formula for the lateral surface area of a right cone is LA= Πrs

All we have to do is plug in and solve.

LA= Π(3)(5)
LA = 15Π
LA = 47.1238898

The lateral surface area is around 48 inches.
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3 years ago
Read 2 more answers
What is the total monthly payment for this mortgage? Principal Per Month $750 Interest Per Month $120 Property Tax Per Year 0.5
m_a_m_a [10]
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4. A random variable X has a mean of 10 and a standard deviation of 3. If 2 is added to each value of X, what will the new mean
Ede4ka [16]

Adding 2 to each value of the random variable X makes a new random variable X+2. Its mean would be

E[X+2]=E[X]+E[2]=E[X]+2

since expectation is linear, and the expected value of a constant is that constant. E[X] is the mean of X, so the new mean would be

E[X+2]=10+2=12

The variance of a random variable X is

V[X]=E[X^2]-E[X]^2

so the variance of X+2 would be

V[X+2]=E[(X+2)^2]-E[X+2]^2

We already know E[X+2]=12, so simplifying above, we get

V[X+2]=E[X^2+4X+4]-12^2

V[X+2]=E[X^2]+4E[X]+4-12^2

V[X+2]=(V[X]+E[X]^2)+4E[X]-140

Standard deviation is the square root of variance, so V[X]=3^2=9.

\implies V[X+2]=(9+10^2)+4(10)-140=9

so the standard deviation remains unchanged at 3.

NB: More generally, the variance of aX+b for a,b\in\mathbb R is

V[aX+b]=a^2V[X]+b^2V[1]

but the variance of a constant is 0. In this case, a=1, so we're left with V[X+2]=V[X], as expected.

5 0
3 years ago
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