2 years ago

Construct a 96% confidence interval if a sampling distribution has a mean of 20, standard deviation of 5, and size of 100?

1 answer:

6 0

Answer:

wryestudrytfuygiuhi'ojpokplkojih;uglyfkdtrjsezdfxh jshfxdgjcfkhgvbj.k/nl

Step-by-step explanation:

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kvv77 [185]

The answer could be
D
but i’m not a 100% sure

4 0

3 years ago

nydimaria [60]

Answer: (-3,2) im pretty sure

4 0

3 years ago

nordsb [41]

Answer: 0, 4

Step-by-step explanation:

8 0

2 years ago

ivanzaharov [21]

Answer: The simplification is $5*a^{-9}*b^{-9}$

Step-by-step explanation:

Here we need to use the property:

$\frac{a^n}{a^m} = a^{n - m}$

We have the expression:

$\frac{25*a^{-5}*b^{-8}}{5*a^{4}*b}$

We can separate it in parts with the same base, then we can rewrite this as:

$\frac{25*a^{-5}*b^{-8}}{5*a^{4}*b} = \frac{25}{5} \frac{a^{-5}}{a^4} \frac{b^{-8}}{b}$

Using the first property we can rewrite this as:

$\frac{25}{5} \frac{a^{-5}}{a^4} \frac{b^{-8}}{b} = 5*a^{-5 - 4}*b^{-8 - 1} = 5*a^{-9}*b^{-9}$

6 0

3 years ago

Gelneren [198K]

20÷2=10 ( gallons half full)

10+5=15 ( gallons you add)

The tank has 15 gallons and is 75% full

8 0

3 years ago