Question

Given f(x) = 52x, evaluate f-1), f(o), and K2). 01/25, 1, 625

Answer 1

Answer:

$f(-1) = \frac{5}{2}$

$f(0) = 5$

$f(2) = 20$

Step-by-step explanation:

Given

$f(x) = 5(2^x)$

Required

Determine f(-1); f(0) and f(2)

Solving f(-1)

In this case, we simply take x as;

$x = -1$

Substitute -1 for x in $f(x) = 5(2^x)$

$f(-1) = 5(2^{-1})$

Apply law of indices

$f(-1) = 5 * \frac{1}{2}$

$f(-1) = \frac{5}{2}$

Solving f(0)

In this case, we simply take x as;

$x = 0$

Substitute 0 for x in $f(x) = 5(2^x)$

$f(0) = 5(2^0)$

$f(0) = 5(1)$

$f(0) = 5$

Solving f(2)

In this case, we simply take x as;

$x = 2$

Substitute 2 for x in $f(x) = 5(2^x)$

$f(2) = 5(2^2)$

$f(2) = 5(4)$

$f(2) = 20$