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oksian1 [2.3K]
3 years ago
13

a painting including the frame measures 71 cm by 75 cm How many centimeters of framing were needed to frame the​ painting?

Mathematics
1 answer:
Step2247 [10]3 years ago
8 0
It depends on what is the width of framing and do we want to place it on painting or not but basically it is the circuit

Circuit = 2*71cm + 2*75cm=2*(71cm+75cm)=2*146cm=292cm

Answer:. U need 292cm of framing (at least).
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36% of what number =93.6
Eva8 [605]
The answer is 260. 260 times 36% is equal to 93.6
3 0
3 years ago
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A pack of cinnamon-scented pencils sells for $5.00. What is the sales tax rate if the total cost of the pencils is $5.40?
kolbaska11 [484]

Answer:

The sales tax rate is 5%

Given:

Sales price = 5.00

Total amount paid = 5.25

Sales tax value = Total amount paid - sales price

                         = $5.25 - $5.00 

Sales tax value = $0.25

Sales tax rate = Sales tax / Sales price

                       = 0.25/5 

Sales tax rate  = 0.05 or 5%

Read more on Brainly.com - brainly.com/question/930282#readmore

Thanks to <em><u>taskmasters.</u></em>

Step-by-step explanation:

6 0
3 years ago
The area of a circle 220mm in diameter is approximately how many times greater than the area of a circle 30mm in diameter?
zmey [24]
The first circle is approximately 44 times greater than the second cirle

Radius = 110 mm
110² = 10,000 mm² = Area

Radius = 15 mm
15² = 225 mm² = Area

Hope this helps!

5 0
4 years ago
What is an equation of the line that passes through the point (-6,-4)(−6,−4) and is parallel to the line x+6y=12x+6y=12?
masya89 [10]

Answer:

x + 6y + 30 = 0

Step-by-step explanation:

x + 6y = 12

6y = -x + 12

y = -⅙x + 2

Slope: -⅙

y - (-4) = -⅙(x - (-6))

y + 4 = -⅙(x + 6)

-6y - 24 = x + 6

x + 6y + 30 = 0

4 0
4 years ago
Consider the following function.f(x) = 16 − x2/3Find f(−64) and f(64).
malfutka [58]

Answer: f(-64)=0

f64)=0

Step-by-step explanation:

The given function : f(x)=16-x^{2/3}

When we substitute x= -64, we get

f(x)=16-(-64)^{2/3}

Since , 64=4\times4\times4=4^3

So, -64=-4\times-4\times-4=-4^3

That means  f(-64)=16-(-64)^{2/3}=16-(-4^3)^{2/3}

=16-(-4)^2=16-(-4\times-4)=16-16=0

i.e. f(-64)=0

Similarly, When we substitute x= 64, we get

f(x)=16-(64)^{2/3}

Since , 64=4\times4\times4=4^3

That means  f(64)=16-(64)^{2/3}=16-(4^3)^{2/3}

=16-(4)^2=16-16=0

i.e. f64)=0

3 0
4 years ago
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