Find f(4) when f(x)=4x^2 - 2 x - 4
1 answer:
Answer:
52
Step-by-step explanation:
(I replaced
with
since we are to find
.)
(By the order of operations, we take care of the exponents before whatever else we have here.)
(By the order of operations, we take care of the multiplication as we see if left to right.)
(By the order of operations, we perform addition/subtraction as we see it left to right.)
(This completes the simplification.)
We could have also put this in our calculator as:
4(4)^2 - 2(4) - 4
This would have returned 52.
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Answer:
Step-by-step explanation:
The standard form of a quadratic equation is 
, while the vertex form is:
, where (h, k) is the vertex of the parabola.
What we want is to write
as
First, we note that all the three terms have a factor of 3, so we factorize it and write:
.
Second, we notice that
are the terms produced by 
, without the 9. So we can write:
, and substituting in we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
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Answer:
What we want is to write
First, we note that all the three terms have a factor of 3, so we factorize it and write:
Second, we notice that
Finally, distributing 3 over the two terms in the brackets we have:
Answer: