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Nata [24]
3 years ago
14

Find f(4) when f(x)=4x^2 - 2 x - 4

Mathematics
1 answer:
prisoha [69]3 years ago
8 0

Answer:

52

Step-by-step explanation:

f(x)=4x^2-2x-4

f(4)=4(4)^2-2(4)-4 (I replaced x with (4) since we are to find f(4).)

f(4)=4(16)-2(4)-4    (By the order of operations, we take care of the exponents before whatever else we have here.)

f(4)=64-8-4           (By the order of operations, we take care of the multiplication as we see if left to right.)

f(4)=56-4              (By the order of operations, we perform addition/subtraction as we see it left to right.)

f(4)=52                 (This completes the simplification.)

We could have also put this in our calculator as:

4(4)^2 -  2(4)  -  4

This would have returned 52.

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4 0
3 years ago
8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

7 0
2 years ago
Help with this question? thx
Sedbober [7]
EXPLANATION:
1.25 + 0.8 + 2.75 = $4.8

ANSWER: $4.8
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