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3 years ago

Which of the following statements cannot be assumed from the diagram?

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

7 0

Answer:

Option (2)

Step-by-step explanation:

Option (1).

Points A, B and D are collinear.

True. (On plane S)

Option (2).

Points A, B, C and E are coplanar.

False.

(Points A, B and D are on plane S and points C and E are on plane R)

Option (3).

BE intersects line 'n' at point B.

True.

Option (4).

CB ⊥ AD

(CB lies on plane R and AD lies on perpendicular plane S).

Option (5).

Line 'm' ⊥ plane R.

True.

(Line m is on plane S which is perpendicular to plane R).

Option (6).

Plane R intersects plane S at line n.

True.

Plane R and Plane S are perpendicular and the point of intersection is line 'n'.

Therefore, Option (2) is incorrect.

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3 years ago

Read 2 more answers

Question 16

Vadim26 [7]

Answer: 175

Step-by-step explanation: total = x + 5y dollars and dollars = 300 so

x + 5y = 300 then since we know y = 200 we can substitute that

x + 5(200) = 300 then subtract x from 200

x + 5(200 - x) = 300 now solve for x

x + 5(200) + 5(-x) = 300 we know 5 times 200 is 1000

x + 1000 - 5x = 300 then subtract 5x - x = -4x

-4x + 1000 = 300 switch around 1000 and 300

-4x = 300 - 1000 subtract 300 - 1000 = -700

-4x = -700 multiply

x = -700/(-4) then finish up and solve

x = 175

hope this helps please mark brainliest if you can

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4 years ago

Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. 2x-y=

Bond [772]

Answer:

The system of linear equations has infinitely many solutions

Step-by-step explanation:

Let's modified the equations and find the answer.

Using the first equation:

$2x-y=5$ we can multiply by 2 in both sides, obtaining:

$2*(2x-y)=2*5$ which can by simplified as:

$4x-2y=10$ which is equal to:

$4x=2y+10$

Considering the second equation:

$=4x+ky=2$

Taking into account that from the first equation we know that: $4x=2y+10$ , we can express the second equation as:

$2y+10+ky=2$ , which can be simplified as:

$(2+k)y=2-10$

$(2+k)y=-8$

$y=-8/(2+k)$

Because (-8) is being divided by (2+k), then (2+k) can't be equal to 0, so:

$2+k=0$ if $k=-2$

This means that k can be any number different than -2, and for each of these solutions, there is a different solution for y, allowing also, different solutions for x.

For example, if k=0 then

$y=-8/(2+0)$ which give us y=-4, and, because:

$4x=2y+10$ if y=-4 then $x=(-8+10)/4=0.5$

Now let's try with k=-1, then:

$y=-8/(2-1)$ which give us y=-8, and, because:

$4x=2y+10$ if y=-8 then $x=(-16+10)/4=-1.5$ .

Then, the system of linear equations has infinitely many solutions

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