The Kenya Airway’s solution was the use of:
- Customer Relationship Management.
- Sourced funds from Jomo Kenyatta International Airport
<h3>What was the problem at Kenya
Airways?</h3>
Kenya Airways is known to be helped by the government and their loss was said to be linked to the pandemic of 2020 and thus they looked for ways to raise funds.
Note that Kenya Airways had issues with unsatisfactory customer relationship and thus they handle this as they said to fly high with Customer Relationship Management.
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When analyzing the industry, Bella Blooms must be concerned about the threat of substitute products or services.
This is one of the threats proposed by <em>Porter</em> in his model of the 5 forces that help to understand market competitiveness.
Bella Blooms must be concerned about the threat of substitute products or services because another fertilizer manufacturer has emerged with the same target market as the company, which could lead to a decrease in Bella Blooms market share.
In the threat of substitute products or services, the customer realizes that they can partially or totally substitute one product for another, which leads companies to actions such as:
- develop focused marketing strategies.
- adapt your processes to market needs.
Therefore, <em>Porter's</em> 5 forces model guarantees that through the analysis of market factors, it is possible to identify its strengths and weaknesses and adapt its strategy to be competitive and profitable in the market.
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Answer:
Explanation below.
Explanation:
The recommendation that I will give or propose is that the agreement must have a legal backing.
This is the best recommendation that a wise person can proposes. It is a show of height of stupidity when an individual go into conjunction with another person without any written agreement that is backed legally. This because, when there is a problem in the future, the documents will be a way to solve it.
The other secondary option is written and signed agreement with video recording. This is not as good as the one mentioned above, but can still be considered as an alternative.
Answer: (a) $197,500
(b) $ 189,500
Explanation:
Given : The marginal cost function : 
To find the cost function, we need to integrate the above function with respect to x.
Now, the additional cost incurred in dollars when production is increased from 100 units to 150 units will be:-
![\int^{150}_{100}\ C'(x)\ dx\\\\=\int^{150}_{100} (4000-0.4x)\ dx\\\\=[4000x-\dfrac{0.4x^2}{2}]^{150}_{100}\\\\=[4000(150)-\dfrac{0.4(150)^2}{2}-4000(100)+\dfrac{0.4(100)^2}{2}]\\\\=[600000-4500-400000+2000]\\\\=197500](https://tex.z-dn.net/?f=%5Cint%5E%7B150%7D_%7B100%7D%5C%20C%27%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B150%7D_%7B100%7D%20%284000-0.4x%29%5C%20dx%5C%5C%5C%5C%3D%5B4000x-%5Cdfrac%7B0.4x%5E2%7D%7B2%7D%5D%5E%7B150%7D_%7B100%7D%5C%5C%5C%5C%3D%5B4000%28150%29-%5Cdfrac%7B0.4%28150%29%5E2%7D%7B2%7D-4000%28100%29%2B%5Cdfrac%7B0.4%28100%29%5E2%7D%7B2%7D%5D%5C%5C%5C%5C%3D%5B600000-4500-400000%2B2000%5D%5C%5C%5C%5C%3D197500)
Hence, the additional cost incurred in dollars when production is increased from 100 units to 150 units= $197,500
Similarly, the additional cost incurred in dollars when production is increased from 500 units to 550 units :-
![\int^{550}_{500}\ C'(x)\ dx\\\\=\int^{550}_{500} (4000-0.4x)\ dx\\\\=[4000x-\dfrac{0.4x^2}{2}]^{550}_{500}\\\\=[4000(550)-\dfrac{0.4(550)^2}{2}-4000(500)+\dfrac{0.4(500)^2}{2}]\\\\=[2200000-60500-2000000+50000]\\\\=189,500](https://tex.z-dn.net/?f=%5Cint%5E%7B550%7D_%7B500%7D%5C%20C%27%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B550%7D_%7B500%7D%20%284000-0.4x%29%5C%20dx%5C%5C%5C%5C%3D%5B4000x-%5Cdfrac%7B0.4x%5E2%7D%7B2%7D%5D%5E%7B550%7D_%7B500%7D%5C%5C%5C%5C%3D%5B4000%28550%29-%5Cdfrac%7B0.4%28550%29%5E2%7D%7B2%7D-4000%28500%29%2B%5Cdfrac%7B0.4%28500%29%5E2%7D%7B2%7D%5D%5C%5C%5C%5C%3D%5B2200000-60500-2000000%2B50000%5D%5C%5C%5C%5C%3D189%2C500)
Hence, the additional cost incurred in dollars when production is increased from 500 units to 550 units = $ 189,500
Answer:
A) 0.023
Explanation:
Sample size = 1,000
Number of defectives collected from Machine #1 = 23
So, the sample proportion of defectives for machine #1 = Number of defective output / Sample size = 23/1000 = 0.023
