All categories

2 years ago

How do I know a table is linear

Mathematics

2 answers:

bonufazy [111]2 years ago

4 0

Answer:

You can tell if a table is linear by looking at how X and Y change. If, as X increases by 1, Y increases by a constant rate, then a table is linear.

Step-by-step explanation:

Hope this helped~

Mama L [17]2 years ago

4 0

Answer:

You can tell if a table is linear by looking at how X and Y change.If,as X increases by 1, Y increases by a constant rate,then a table is linear.

You might be interested in

A normally distributed set of numbers has a mean of 75 and a standard deviation of 7.97. What percentage of values lies between

lana [24]

Answer:

63% of the values lies between 70 and 85.

Step-by-step explanation:

We are given that a normally distributed set of numbers has a mean of 75 and a standard deviation of 7.97.

Let X = Set of numbers

The z-score probability distribution for is given by;

Z = $\frac{ X -\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean value = 75

$\sigma$ = standard deviation = 7.97

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, percentage of values that lies between 70 and 85 is given by = P(70 < X < 85) = P(X < 85) - P(X $\leq$ 70)

P(X < 85) = P( $\frac{ X -\mu}{\sigma}$ < $\frac{ 85-75}{7.97}$ ) = P(Z < 1.25) = 0.89435 {using z table}

P(X $\leq$ 70) = P( $\frac{ X -\mu}{\sigma}$ $\leq$ $\frac{ 70-75}{7.97}$ ) = P(Z $\leq$ -0.63) = 1 - P(Z < 0.63)

= 1 - 0.73565 = 0.26435

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.25 and x = 0.63 in the z table which has an area of 0.89435 and 0.73565 respectively.

Therefore, P(70 < X < 85) = 0.89435 - 0.26435 = 0.63 or 63%

Hence, 63% of the values lies between 70 and 85.

6 0

3 years ago

Mrs. Chu's famous peanut butter cookies call for 1 cup of peanut butter for every 1/2 of a cup of oil. Today, she wants to make

lesantik [10]

Answer:

she should use 2 cups of peanut butter

Step-by-step explanation:

to know the answer to that

use this equation (pb is peanut butter &o is oil)

1cup of pb=1/2 cup of o

?=1 cup of o

1×1÷1/2= 1×1×2/1=2co cups of pb

5 0

2 years ago

Solve for p: p – 23 = -3 A. p = 20 B. p = -20 C. p = -26 D. p = 69

Alekssandra [29.7K]

P-23=-3
+23 +23

P=20

so the answer is A

6 0

1 year ago

Please help me I'm stuck

AnnZ [28]

I don’t see any typing ?

6 0

3 years ago

The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min. If one such class is r

svp [43]

Answer:

0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

$P(c \leq X \leq d) = \frac{d - c}{b - a}$

The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min.

This means that $a = 50, b = 52$

If one such class is randomly selected, find the probability that the class length is between 51.5 and 51.7 min.

$P(51.5 \leq X \leq 51.7) = \frac{51.7 - 51.5}{52 - 50} = \frac{0.2}{2} = 0.1$

0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.

3 0

2 years ago