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2 years ago

Heeeeeyyyyy someone can aswer plz? Thx

Mathematics

1 answer:

worty [1.4K]2 years ago

8 0

Answer:

x=65+32 [ being ext. angle of triangle is equal to the sum of two opposite interior angle]

therefore x=97°

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I'm solving for UW. And we're using pythagorean theorem.

Alik [6]

UW = 45
a squared + b squared = c squared
- 6^2 + x^2 = 9^2
- 36 + x = 81
- (subtract 36 from both sides)
- x = 45

i'm pretty sure this is right and i hope it helps you!

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3 years ago

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By what factor does the intensity increase for each whole number increase in the Richter scale? Use your understanding of logari

nataly862011 [7]

Answer:

Because of the logarithmic basis of the scale, each whole number increase in magnitude represents a tenfold increase in measured amplitude; in terms of energy, each whole number increase corresponds to an increase of about 31.6 times the amount of energy released, and each increase of 0.2 corresponds to approximately a doubling of the energy released.

Step-by-step explanation:

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3 years ago

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Zepler [3.9K]

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3 years ago

As x → − ∞ , f ( x ) = − 3 . As x → ∞ , f ( x ) = − 3

Ludmilka [50]

Answer:

Step-by-step explanation:

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2 years ago

A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.

AVprozaik [17]

Answer:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

8 0

3 years ago