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Svet_ta [14]
2 years ago
5

Heeeeeyyyyy someone can aswer plz? Thx

Mathematics
1 answer:
worty [1.4K]2 years ago
8 0

Answer:

b)

x=65+32 [ being ext. angle of triangle is equal to the sum of two opposite interior angle]

therefore x=97°

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Tiffany makes scarves and sells them at a neighborhood
Phoenix [80]
<span>n(30-14)-25=100
16n=125
n=7.8125 scarves a day, or 8 scarves a day must be sold, in order to make a profit of at least $100.!


I hope this helps!</span>
4 0
3 years ago
How do i do this. will give brainliest
Tomtit [17]

Try this option ↓

Step-by-step explanation:

1) according to the condition two angles are equal, then two sides are equal also, it means

2) √x+4=√(5x+4);

3) the 'x' can be calculated if to solve this equation:

\sqrt{x} +4=\sqrt{5x+4};

x+16+8\sqrt{x} =5x+4;

4x-12=8\sqrt{x} ;\ => \ x-2\sqrt{x} -3=0;

\left \{ {{\sqrt{x} =-1} \atop {\sqrt{x} =3}} \right. \ => \ x=9.

4) finally, answer: 9.

4 0
2 years ago
QT 1.
erma4kov [3.2K]
1: 3.2
2: B. 1.6
3: C. 6.4
4: D. 17.92

I'm unable to see the table for 5, are you able to attach it?
5 0
3 years ago
Drag the correct graph to the box under the equation it corresponds to.<br><br> HELP YOU GUYS
ra1l [238]

Answer:

<h2>See below</h2>

Step-by-step explanation:

I can't drag and drop the graphs, but I can graph the equations shown. Then, all you will have to do is match the graphs shown the the graph that I will provide.

<h3>EQUATION 1: y = x² - 2</h3>

Graph Properties:

Opens up

Vertex is 0, -2

Axis of symmetry is x = 0

Graph photo shown in file called equation 1 graph

<h3>EQUATION 2: y = 2x²</h3>

Graph Properties:

Opens up

Vertex is 0, 0

Axis of symmetry is x = 0

Graph photo shown in file called equation 2 graph

<h3>EQUATION 3: y = (x - 2)²</h3>

Graph Properties:

Opens up

Vertex is 2, 0

Axis of symmetry is x = 2

Graph photo shown in file called equation 3 graph

I'm always happy to help :)

5 0
3 years ago
Use the definition mtan=lim
Leokris [45]

(a) mtan refers to the slope of the tangent line. Given <em>f(x)</em> = 9 + 7<em>x</em> ², compute the difference quotient:

\dfrac{f(x+h)-f(x)}h = \dfrac{(9+7(x+h)^2)-(9+7x^2)}h = \dfrac{(9+7x^2+14xh+7h^2)-9-7x^2}h = \dfrac{14xh+7h^2}h

Then as <em>h</em> approaches 0 - bearing in mind that we're specifically considering <em>h</em> <em>near</em> 0, and not <em>h</em> = 0 - we can eliminate the factor of <em>h</em> in the numerator and denominator, so that

m_{\rm tan} = \displaystyle \lim_{h\to0}\frac{f(x+h)-f(x)}h = \lim_{h\to0}\frac{14xh+7h^2}h = \lim_{h\to0}(14x+7h) = 14x

and so the slope of the line at <em>P</em> (0, 9), for which we take <em>x</em> = 0, is 0.

(b) The equation of the tangent line is then <em>y</em> = 9.

4 0
2 years ago
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