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liq [111]
3 years ago
14

A class of 260 students went on a field trip. They took 12 vehicles, some cars and some buses. Find the number of cars and the n

umber of buses they took if each car holds 5 students and each bus holds 25 students. Let c= cars and b= buses.
Mathematics
1 answer:
Afina-wow [57]3 years ago
5 0
The equation is 5c+25b=260 when c+b=12. rearrange that into 12-b=c. substitute and you get 5(12-b)+25b=260. b=10. 12-10=2, so 10 buses and 2 cars were used as transportation for the field trip.
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Four plumbers estimated the length of the radius of a cylindrical pipe. The estimates made by
o-na [289]

Answer:

B. \frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25},  \frac{9}{100}

Step-by-step explanation:

The question is not properly presented. See attachment for proper presentation of question

From the attachment, we have that:

W = \frac{3}{25}

X = \frac{\sqrt{3}}{11}

Y = \frac{9}{100}

Z = \frac{\pi}{24}

Required

Order from greatest to least

First, we need to simplify each of the given expression (in decimals)

W = \frac{3}{25}

W = 0.12

X = \frac{\sqrt{3}}{11}

Take square root of 3

X = \frac{1.73205080757}{11}

X = 0.15745916432

X = 0.16 --- approximated

Y = \frac{9}{100}

Y = 0.09

Z = \frac{\pi}{24}

Take π as 3.14

Z = \frac{3.14}{24}

Z = 0.13083333333

Z = 0.13  --- approximated

List out the results, we have:

W = 0.12    X = 0.16    Y = 0.09    Z = 0.13

Order from greatest to least, we have:

X = 0.16     Z = 0.13      W = 0.12       Y = 0.09

Hence, the order of arrangement is:

X = \frac{\sqrt{3}}{11}     Z = \frac{\pi}{24}      W = \frac{3}{25}      Y = \frac{9}{100}

i.e.

\frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25},  \frac{9}{100}

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Step-by-step explanation:

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The answer to the question

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