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LiRa [457]
3 years ago
8

Please solve the equation X^2+3x+3=0

Mathematics
1 answer:
Degger [83]3 years ago
4 0
<u>x² + 3x + 3 = 0</u>

I can tell by looking that there's no easy way to factor the left side,
so we'll have to use the Quadratic formula.

Before doing that, let's just take a look at the discriminant:

( B² - 4AC ) = (9) - (4 x 3 x 1) = (9 - 12) = -3 .
The discriminant is negative, so we know that the roots will be complex conjugates.

Again:  <u>x² + 3x + 3 = 0</u>

x = (1/2) [ -3 plus or minus the square root of (-3) ]

<u>x = -3/2 + (1/2) j√3</u>
and
<u>x = - 3/2 - (1/2) j√3</u>
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Decide if each answer will be less than or greater than the original number. Drag each to the correct category
enot [183]

That's a question about percentage.

Let's imagine that we want to know how much is 90% of 200. To do this calculation, we should multiply 200 by 90 and then divide the result by 100. We do that because 90% is the same thing that \frac{90}{100} =0,9. So, 90% of 200 is equal to:

\frac{200\cdot90}{100} =\\\\\frac{18000}{100} =\\\\180

Now, imagine that you would like to know how much is 100% of 999. First, we multiply 999 by 100 and divide the result by 999. So, 100% of a number is equal to itself. That's a very important information, because it's possible to understand this:

  • If the percentage is less than 100%, the result is less than original number.
  • If the percentage is equal to 100%, the result is equal to the original number.
  • If the percentage is greater than 100%, the result is greater than original number.

Now, we can solve our problem! \o/

The options that the percentage is less than 100% are: 35% of 300, 62% of 182 and 89% of 525. Therefore, their answers will be less than the original number.

And, the option that the percentage is greater than 100% are: 250% of 18, 300% of 250 and 120% of 72. So, their answers will be greater than the original number.

On the image, you can see the answer in a table.

I hope I've helped. ^^

Enjoy your studies! \o/

7 0
3 years ago
25 POINTS Lines a,b,c, and d are in the same plane. Line a is parallel to line c. Lines d and c are perpendicular to line d. Bas
polet [3.4K]

Assuming that the actual question reads lines b and c are perpendicular to line d

we are given that c is perpendicular to line d and parallel to line a.  Since b is also perpendicular to line d, a b and c must all be parallel (draw it out will make a lot more sense)

So b is also parallel to line a

5 0
4 years ago
Emily and Holly took a road trip together. Emily drove at an average of 45 miles per hour for the first 3/7 of the total distanc
Elan Coil [88]
Emily drove 3/7 of the total distance and holly drove the rest which explains that holly drove 4/7 of the whole distance.

if 4 parts of the distance equals 24 miles, then 1 part would be 24/4 is 6.
since emily drove 3 parts of the whole distance, it is 6 × 3 = 18 miles.

travelling time of emily = 18/45 = 0.4 hr
travelling time of holly = 24/54 = 0.4 hr
--> total traveling time = 0.8 hr

i hope it is right
3 0
3 years ago
Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.
gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant  is  mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is  mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)

The partial derivatives of a function are f x and f y.

\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\

&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}

In conclusion,  the area is

A=3 √4 units ^2

Read more about the plane

brainly.com/question/1962726

#SPJ4

5 0
1 year ago
Help with this algebra question
choli [55]
If two lines are perpendicular, the slope of one of the lines is the negative reciprocal of the other. Since we know the slope for one of our lines, 2m lets find the other:
m=- \frac{1}{2}

Now, lets use the point-slope formula to complete the equation of our perpendicular line:
y-y_{1}=m(x-x_{1})
y-5=- \frac{1}{2} (x-2)
y-5=- \frac{1}{2}x+1
y=- \frac{1}{2} x+6

We can conclude that our perpendicular line is y=- \frac{1}{2} x+6
3 0
4 years ago
Read 2 more answers
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