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kolezko [41]
3 years ago
8

CAN ANYBODY HELP ME WITH THIS ONE TOO!!!!

Mathematics
2 answers:
grandymaker [24]3 years ago
8 0

Answer: K

<u>Step-by-step explanation:</u>

Compare the equations of:  h = -t² + 4t + 5  and  h = -t² + 4t + 12

h = -t² + 4t + 5:

  • c-value is 5
  • ⇒ h-intercept is 5
  • intercept form: h = -(t + 1)(t - 5)
  • ⇒ intercepts are t = -1 and t = 5
  • vertex form: h = -(x - 2)² + 9
  • ⇒ vertex is (2, 9)
  • ⇒ maximum value of h is 9

h = -t² + 4t + 12:

  • c-value is 12
  • ⇒ h-intercept is 12
  • intercept form: h = -(t + 2)(t - 6)
  • ⇒ intercepts are t = -2 and t = 6
  • vertex form: h = -(x - 2)² + 16
  • ⇒ vertex is (2, 16)
  • ⇒ maximum value of h is 16

The only value that changed between these two equations is "c", however the h-intercepts, maximum values, and t-intercepts are all different.  

This is because the c-value shifted the entire parabola up.  Shifting the parabola up <em>or down</em> will affect the intercepts and the maximum value of the vertex.

SashulF [63]3 years ago
7 0

Answer:

I only

Step-by-step explanation:

given h = - at² + bt + c

the vertex = - \frac{b}{2a}

Thus altering a or b effects the position of the vertex

and the maximum value is the value of the vertex

Altering c effects the h-intercept only



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