If sum of numbers (a) +(b) is 1419 and
(a) and (b) are <span>neighbors , whe have:
a + b = 1419 and b-a = 1;
<=> </span>a + b = 1419 and <span>a = b-1 ;
so we have b-1 + b = 1419 <=> 2b = 1420 <=> b=710 and a = 709
Answer: 710 and 709
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Answer:
I think that the answer would be C because you have to multiply the term at the top. This would mean you would not do C. Sorry if this is wrong. At least you have your eliminating process now. lol so doing C is out of the box, which makes C your answer.
Step-by-step explanation:
Answer:
57 deg
Step-by-step explanation:
Rhombus ABCD has diagonals AC and BD which intersect at point E.
The diagonals of a rhombus divide the rhombus into 4 congruent triangles.
If you find the measures of the angles of one of the triangles, then you know the measures of the angles of all 4 triangles.
Also, the diagonals of a rhombus are perpendicular.
Look at triangle BCE.
m<BCE = 33
m<BEC = 90
m<BCE + m<BEC + m<CBE = 180
33 + 90 + m<CBE = 180
m<CBE = 57
<ABE in triangle ABE corresponds to <CBE in triangle BCE.
m<ABE = m<CBE = 57
Answer: 57 deg