We have that
<span>p(t)=-3t^2+18t-4
using a graphing tool, we can see the maximum of the graph
(see the attached figure)
A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?
</span>
Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)
<span>B) What is the maximum profit?
23 (hundred of thousand of dollars) = 2.300.000 dollars
</span>c) What time will it be two late?
(This is the time when the graph crosses zero and the profits turn into losses )
5.77 years, or an estimate of about 69 months.
Answer:
D. x=1
Step-by-step explanation:
Image can be rewritten as 3x + 6 = 9.
Solve for x.
3x +6 = 9
Isolate x by subtracting 6 from both sides.
3x = 3
Get rid of the 3 by dividing by 3 on both sides.
x = 1
Hope this helped.
Answer:
$3.98(estimated)
Step-by-step explanation:
3c (cake) + 2(2c - 11) (bread) = 5.87
3c + 4c - 22 = 5.87
7c - 22 = 5.87
7c = 5.87 + 22
7c = 27.87
c = 3.98
Answer:
First, find two points on the graph:
- (x₁, y₁) = (0, 2)
- (x₂, y₂) = (2, 8)
Slope = 
16 + (-3) = 16 - 3 = 13