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Talja [164]
3 years ago
13

in a class of 34 students 19 of them are girls what percentage of the class are girls to 1 decimal place

Mathematics
2 answers:
zysi [14]3 years ago
7 0

\frac{19}{34} x 100 = 55.9%

motikmotik3 years ago
6 0

Answer:

55.9% of the class are girls

Step-by-step explanation:

19/34 = 0.559

0.559 x 100 = 55.9%

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Peter enrolled $80,000 worth of debt with National Debt Relief. Peter’s fee for the service is 20% of the enrolled debt. How muc
Georgia [21]

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16000

Step-by-step explanation:

7 0
1 year ago
Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 66 kmh faster than the othe
goldfiish [28.3K]

Answer:

  • The rate of planes: 926 km/h and 860 km/h

=========================

<h3>Given</h3>

  • Two planes travel in opposite directions,
  • One plane travels 66 km/h faster than the other,
  • The distance between the two planes after 6 hours is 10716 km.

<h3>To find</h3>

  • The rate of of each plane

<h3>Solution</h3>

The distance traveled by two planes in an hour is:

  • 10716/6 = 1786 km/h

Let the rate of one plane be x, then the other plane's rate is x - 66.

The sum of two rates is the distance traveled in one hour:

  • x + x - 66 = 1786
  • 2x - 66 = 1786
  • 2x = 1786 + 66
  • 2x = 1852
  • x = 1852/2
  • x = 926

So the rate of one plane is 926 km/h and of the other plane is:

  • 926 - 66 = 860 km/h
3 0
2 years ago
Suppose $n$ is a positive integer such that $6n$ has exactly 9 positive divisors. How many prime numbers are divisors of $6n$
zvonat [6]

The number of prime divisors of "6n" is 2 numbers 2 and 3

Given

"n"  = 6    

thus 6n  = 6(6) = 36

The positive divisors are   1, 2, 3, 4, 6, 9, 12, 18 and 36

So, the number of prime divisors of "6n" is 2 numbers 2 and 3.

The prime factors of a positive integer are the top numbers that divide that integer exactly. The technique of finding those numbers is known as integer factorization or prime factorization.

The fundamental theorem of mathematics says that every positive integer has a completely unique prime factorization.

Learn more about prime factorization here: brainly.com/question/1081523

#SPJ4

6 0
2 years ago
PLEASE HELP! WILL MARK BRAINLIEST!
makkiz [27]

Answer:

The maximum height a rider will experience is 55 feet.

Step-by-step explanation:

Let's start writing the function that defines the path of a seat on the new Ferris wheel. This function will depend of the variable ''t'' which is time.

X(t)=(x,y)

In which X(t) are the coordinates of the seat (the x - coordinate and the y - coordinate) that depend from time.

''x'' and ''y'' are functions that depend from the variable ''t''.

For this exercise :

X(t)=[-25sin(\frac{\pi}{30}t);-25cos(\frac{\pi}{30}t)+30]

In order to find the maximum height a rider will experience we will study the behaviour of the y - component from the function X(t).

The function to study is y(t)=-25cos(\frac{\pi}{30}t)+30

To find its maximum, we will derivate this function and equalize it to 0. Doing this, we will find the ''critical points'' from the function.

⇒ y(t)=-25cos(\frac{\pi}{30}t)+30  ⇒

y'(t)=\frac{5}{6}\pi sin(\frac{\pi}{30}t)

Now we equalize y'(t) to 0 ⇒

y'(t)=0 ⇒ \frac{5}{6}\pi sin(\frac{\pi}{30}t)=0

In this case it is easier to look for the values of ''t'' that verify :

sin(\frac{\pi}{30}t)=0

Now we need to find the values of ''t''. We know that :

sin(0)=0\\\\sin(\pi)=0\\sin(-\pi)=0

Therefore we can write the following equivalent equations :

\frac{\pi}{30}t=0 (I)

\frac{\pi}{30}t=\pi (II)

\frac{\pi}{30}t=-\pi (III)

From (I) we obtain t_{1}=0

From (II) we obtain t_{2}=30

And finally from (III) we obtain t_{3}=-30

We found the three critical points of y(t). To see if they are either maximum or minimum we will use the second derivative test. Let's calculate the second derivate of y(t) :

y'(t)=\frac{5}{6}\pi sin(\frac{\pi}{30}t) ⇒

y''(t)=\frac{\pi ^{2}}{36}cos(\frac{\pi }{30}t)

Now given that we have an arbitrary critical point ''t_{n}'' ⇒

If y''(t_{n})>0  then we will have a minimun at t_{n}

If y''(t_{n}) then we will have a maximum at t_{n}

Using the second derivative test with t_{1},t_{2} and t_{3} ⇒

y''(t_{1})=y''(0)=\frac{\pi ^{2}}{36} >0 ⇒ We have a minimum for t_{1}=0

y''(t_{2})=y''(30)=\frac{-\pi^{2}}{36} ⇒ We have a maximum for t_{2}=30

y''(t_{3})=y''(-30)=\frac{-\pi^{2}}{36} ⇒ We have a maximum for t_{3}=-30

The last step for this exercise will be to find the values of the maximums.

We can do this by replacing in the equation of y(t) the critical points t_{2} and t_{3} ⇒

y(t_{2})=y(30)=55

y(t_{3})=y(-30)=55

We found out that the maximum height a rider will experience is 55 feet.

3 0
3 years ago
Read 2 more answers
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