Answer:
3. i think 15.5
4. 140*
Step-by-step explanation:
in number 4, d is a vertical angle to the angle measured at 140.
in number 3, QV=SV, so 17=4x-1 18=4x 18/4=x x=4.5
and TS=TQ, so 3(x) + 2 = 3(4.5) + 2 = 13.5 + 2 = 15.5 =TQ
<em> </em><em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>0</em><em>.</em><em>7</em><em>5</em><em>.</em><em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>
12 x 6s - 8 x 4s = 72s - 32s = 40s
Answer:
The correct answer is 15 cm.
Step-by-step explanation:
Let the width of the required poster be a cm.
We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.
Similarly total margin combining both the sides is (4+4=) 8 cm.
So the required printing area of the poster is given by {( a-10 ) × ( a - 8) } 
This area is equal to 125
as per as the given problem.
∴ (a - 10) × (a - 8) = 125
⇒
- 18 a +80 -125 =0
⇒
- 18 a -45 = 0
⇒ (a-15) (a-3) = 0
By law of trichotomy the possible values of a are 15 and 3.
But a=3 is absurd as a
4.
Thus the required answer is 15 cm.
The correct answer is C. F(x)=2 * (0.7)^x