Answer:
Step-by-step explanation:
The straight line equation is:
y = m*x + b Where m is the slope of the line and b the intercept with y-axis, in our case y is the depth of the tank and x (time in lapsus of 3 hours).
The slope m = ( y₂ - y₁ ) / (x₂ - x₁)
We have point A ( 3 , 8 ) and point B ( 6 , 7 )
m = ( 6 - 3 ) / (7 - 8 ) m = -3
We see that each 3 hours time-depth decreases 1 in.
Then to find the depth at the beginning of x-axis
At noon 12 tank was 9 inches, three hours before at 9 in the morning the depth was 10 inches and:
9 in the morning 10
6 in the morning 11
3 in the midnight 12
12 in the night 13
Then 13 is the intercept with y-axis
then the equation is:
h = - 3*x + 13
Note x is time in lapsus of 3 hours
Answer:
Step-by-step explanation:
20%
Answer:
This cannot be solved but it can be simplified
first we open the bracket
so we have
a²- abx/x = 2/3
next we cross multiply so it will be 3(a² - abx) = 2x
we get
3a² - 3abx = 2x
Next we factorise so we can get
3a(a-bx) =2x
I dont know what exactly you where asked but I hop this helps
To elaborate:
To do this problem, we assume that Mr. Sanchez is driving at a constant rate.
According to this information, he has driven 120 mi in 3 hr. To find how much he drives in 5 hr, we first have to find how many mi he drives in 1 hour. To do this, we divide 120 miles by 3 hours, since we assume that he managed to drive an equal amount in each hour.
120/3=40
Therefore Mr. Sanchez drove at a rate of 40 mph.
However, this isn't the final answer. 40 miles is the distance for one hour of driving. To find the distance for 5 hours, we have to multiply the distance by 5 as well.
40 times 5=200
In conclusion, Mr. Sanchez will drive 200 miles in 5 hours.
